在Java中使用BigInteger查找析因? [英] Find factorials using BigInteger in java?

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本文介绍了在Java中使用BigInteger查找析因?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试查找t个数的阶乘,并且每个n的输入都由用户提供.约束是;

I am trying to find the factorial of t numbers and input for each number n is provided by the user.The constraints are;

1 < t <= 100
1 < n <= 100

我的代码是:

import java.util.Scanner;
import java.math.BigInteger;

public class fact {
    public static void main(String args[]) {
        int t = 0, i = 0;
         BigInteger result = BigInteger.valueOf(1);
         BigInteger x1 = BigInteger.ONE;
         Scanner sc = new Scanner(System.in);
         t = sc.nextInt();
         BigInteger a[] = new BigInteger[t];

        for(i = 0; i < t; i++) {
           a[i] = BigInteger.valueOf(sc.nextInt());
        }

        for(i = 0; i < t; i++) {
            while(!a[i].equals(x1)) {
               result = result.multiply(a[i]);
               a[i].subtract(BigInteger.valueOf(1));
            }
            System.out.println(result);
            result = x1;
        }
    }
}

上面的代码我没有收到任何错误,它可以很好地编译,当我执行它时,它只会不断获取输入,而不会输出任何输出.

I am receiving no errors for the above code it compiles fine and when I execute it just keeps on getting input and no output is printed.

推荐答案

在这一行:

a[i].subtract(BigInteger.valueOf(1));

因为 BigInteger 是不可变, 返回一个新的BigInteger.您需要存储结果,否则将陷入无尽的循环.更改为

Since BigIntegers are immutable, subtract() returns a new BigInteger. You need to store the result, or you will get an endless loop. Change to

a[i] = a[i].subtract(BigInteger.ONE);

这篇关于在Java中使用BigInteger查找析因?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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