如何使用或运算符组合2个字符串? [英] how to combine 2 string using or operator?

问题描述

String a="b5a99e49708ecf072f189b4f85007c76990ef305";
String b="a7d55b1a392a1f34ab95453817fdd49df140c486";

示例我将字符串转换为十进制"1".是6位.我该如何做7位?并使用或运算符字符串a和b;

Example i converted string to decimal "1". it was 6 bits. how do i do it 7bits? and use or operator string a and b;

这是我的代码

char[] c = a.toCharArray();
char[] d = b.toCharArray();

for (int i = 0; i < str.length(); i++)
{
    r += Integer.toBinaryString(c[i]|d[i]);     
}

推荐答案

如果我正确理解，您只需要在二进制字符串中添加正确数量的零即可，所以总共有7位.生成少量固定数量字符的标准技巧是在该字符的恒定字符串上使用String.substring().由于char可以容纳16位，所以我们永远不需要超过16个零:

If I have understood correctly, you just need to prepend the correct number of zeroes to your binary string so there are 7 bits in all. The standard trick to generate a small fixed number of a character is to use String.substring() on a constant string of that character. Since a char fits in 16 bits, we will never need more than 16 zeroes:

    String binaryString = Integer.toBinaryString(ch);
    int missingZeroes = desiredNumberOfBits - binaryString.length();
    if (missingZeroes > 0) {
        binaryString = "0000000000000000".substring(0, missingZeroes) + binaryString;
    }
    System.out.println(binaryString);

如果ch是持有1的char，则上面的打印内容

If ch is a char holding a 1, the above prints

0110001

如果需要的话，您可以填写c[i] | d[i]而不是ch.

You can fill in c[i] | d[i] instead of ch if that is what you require.

您可能要添加防御性检查，以确保Integer.toBinaryString()中的字符串不是太长.

You may want to add a defensive check that the string from Integer.toBinaryString() is not already too long.

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