在DataGridView上使用DataTable显示小图像(图标) [英] Using DataTable at DataGridView to display small images(Icon)
问题描述
我想使用DataTable在Datagridview上使用图像.
I'd like to use image at Datagridview using DataTable.
RadioButton只是本文的一种简单问题格式.
RadioButton is just a simple question format for this post.
让我为此澄清一下.
如何使用绑定样式在datagridview上添加此图像"或该图像"?
(因为
我认为,这比常规方法要快.我制作了500行图像和文字-它们都是16 * 16和简短的单词. 如果我重画它,我花了 20秒.二十!这是胡说八道.我尝试了双缓冲区"解决方法,但没有更好的方法.)
I thought, it is faster then the normal ways. I made 500 lines of images and texts -both of them are 16*16 and short words. If I redraw it, it took me 20 seconds. Twenty !!!! This is a nonsense. I have tried "Double buffer" workarounds, but nothing was better.)
我写了密码.
这只是DataGridView上RadioButton的起点.
It is just a start point for RadioButton on DataGridView.
到目前为止一切都很好.
So far so good.
我在上面制作了五张图像.
I made five images on it.
喜欢这个.
dataGridView1.RowCount = 5;
dataGridView1.Rows[0].Cells[0].Value = Properties.Resources.WhiteBall;
dataGridView1.Rows[1].Cells[0].Value = Properties.Resources.BlueBall;
dataGridView1.Rows[2].Cells[0].Value = Properties.Resources.WhiteBall;
dataGridView1.Rows[3].Cells[0].Value = Properties.Resources.WhiteBall;
dataGridView1.Rows[4].Cells[0].Value = Properties.Resources.WhiteBall;
问题.
如何使用"DataTable绑定样式"获得相同的结果?
How can I make the same result using "DataTable binding style" ?
我只有错误行中需要正确的数据类型".
I had only error "Needs correct DataType at Rows".
我第二次尝试的代码是;
My codes for 2nd try is;
DataTable myTable = new DataTable();
DataColumn myCoulmn = new DataColumn();
myCoulmn.DataType = Type.GetType("System.Drawing.Bitmap");
myTable.Columns.Add(myCoulmn);
DataRow myRow = myTable.NewRow();
myRow[0] = Properties.Resources.WhiteBall;
myRow[1] = Properties.Resources.BlueBall;
myRow[2] = Properties.Resources.WhiteBall;
myRow[3] = Properties.Resources.WhiteBall;
myRow[4] = Properties.Resources.WhiteBall;
myTable.Rows.Add(myRow);
dataGridView1.DataSource = myTable;
请帮助.
推荐答案
使用DataTable在DataGridView中显示图像
要使图像列使用DataTable
,应使用具有byte[]
数据类型的DataColumn
和DataGridVide
中的DataGridViewImageColumn
.因此,您首先需要将图像转换为字节数组,然后将它们设置为具有字节数组数据类型的数据列的值:
To have an image column using a DataTable
you should use a DataColumn
with byte[]
data type and a DataGridViewImageColumn
in DataGridVide
. So you first need to convert images to byte array then set them as value of a data column with byte array data type:
var imageConverter = new ImageConverter();
var b1 = (byte[])imageConverter.ConvertTo(Properties.Resources.Image1, typeof(byte[]));
var b2 = (byte[])imageConverter.ConvertTo(Properties.Resources.Image2, typeof(byte[]));
var dt = new DataTable();
dt.Columns.Add("Column1", typeof(byte[]));
dt.Rows.Add(b1);
dt.Rows.Add(b2);
this.dataGridView1.DataSource = dt;
为bool列而不是CheckBox绘制RadioButton
使用图像类型不适用于单选按钮.此类DataColumn
的合适数据类型是bool
,列的合适DataGridViewColumn
是DataGridViewCheckBoxColumn
.然后,您可以处理DataGridView
的CellPainting
事件,并使用RadioButtonRenderer
这样绘制单选按钮:
Using image type is not suitable for a radio button. A suitable data type for such DataColumn
is bool
and a suitable DataGridViewColumn
for column is DataGridViewCheckBoxColumn
. Then you can handle CellPainting
event of DataGridView
and draw a radio button using RadioButtonRenderer
this way:
private void Form1_Load(object sender, EventArgs e)
{
var dt = new DataTable();
dt.Columns.Add("Column1", typeof(bool));
dt.Rows.Add(false);
dt.Rows.Add(true);
this.dataGridView1.DataSource = dt;
this.dataGridView1.CellPainting += dataGridView1_CellPainting;
}
void dataGridView1_CellPainting(object sender, DataGridViewCellPaintingEventArgs e)
{
if (e.ColumnIndex == 0 && e.RowIndex >= 0)
{
var value = (bool?)e.FormattedValue;
e.Paint(e.CellBounds, DataGridViewPaintParts.All &
~DataGridViewPaintParts.ContentForeground);
var state = value.HasValue && value.Value ?
RadioButtonState.CheckedNormal : RadioButtonState.UncheckedNormal;
var size = RadioButtonRenderer.GetGlyphSize(e.Graphics, state);
var location = new Point((e.CellBounds.Width - size.Width) / 2,
(e.CellBounds.Height - size.Height) / 2);
location.Offset(e.CellBounds.Location);
RadioButtonRenderer.DrawRadioButton(e.Graphics, location, state);
e.Handled = true;
}
}
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