从字节切片中将位提取到int切片中 [英] Extract bits into a int slice from byte slice

问题描述

我有以下字节切片，我需要从中提取比特并将它们放置在[] int中，因为我打算稍后获取各个比特值.我很难弄清楚该怎么做.

I have following byte slice which from which i need to extract bits and place them in a []int as i intend to fetch individual bit values later. I am having a hard time figuring out how to do that.

下面是我的代码

data := []byte{3 255}//binary representation is for 3 and 255 is 00000011 11111111

我需要的是一点点-> [0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1]

what i need is a slice of bits -- > [0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1]

我尝试了

• 我尝试使用BigEndian将字节片转换为Uint16，然后尝试使用strconv.FormatUint，但是失败，并显示错误panic: runtime error: index out of range
• 看到了许多示例，这些示例使用fmt.Printf函数简单地输出了数字的位表示形式，但对我来说却没有用，因为我需要一个int切片来进一步访问位值.

• I tried converting byte slice to Uint16 with BigEndian and then tried to use strconv.FormatUint but that fails with error panic: runtime error: index out of range
• Saw many examples that simple output bit representation of number using fmt.Printf function but that is not useful for me as i need a int slice for further bit value access.

我需要在这里使用移位运算符吗?任何帮助将不胜感激.

Do i need to use bit shift operators here ? Any help will be greatly appreciated.

推荐答案

一种方法是遍历字节，并使用第二遍循环逐位移动字节值并使用位掩码测试位.并将结果添加到输出切片中.

One way is to loop over the bytes, and use a 2nd loop to shift the byte values bit-by-bit and test for the bits with a bitmask. And add the result to the output slice.

这是它的一个实现:

func bits(bs []byte) []int {
    r := make([]int, len(bs)*8)
    for i, b := range bs {
        for j := 0; j < 8; j++ {
            r[i*8+j] = int(b >> uint(7-j) & 0x01)
        }
    }
    return r
}

测试:

fmt.Println(bits([]byte{3, 255}))

输出(在游乐场上尝试):

[0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1]

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