如何从Java中的int获取最高有效的n位 [英] How to get most significant n bits from int in java

问题描述

我有一个int，我想获取java中的19个最高有效位.我尝试了各种方法，但没有一种起作用. 有人可以帮我吗?

I have an int, and I would like to get the 19 most significant bits in java. I tried all sorts of methods, none of them work. Can someone please help me?

推荐答案

在32位int中，您希望保留19个最高有效位，因此将13个最小保留.然后您右移13位，但必须通过19位模式相加来摆脱可能的符号扩展:

From the 32 bit int, you want to keep the 19 most significant, so discard the 13 least; then you shift right by 13 bits, but have to get rid of the possible sign extension, by anding with a 19 bit pattern:

(myint >> 13) & 0x7ffff

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