我如何从int获得一点? [英] How am I getting a single bit from an int?

问题描述

我了解:

int位=(数字>> 3)& 1;

int bit = (number >> 3) & 1;

请给我左起第3位，所以说8是1000，所以应该是0001.

Will give me the bit 3 places from the left, so lets say 8 is 1000 so that would be 0001.

我不明白的是，& 1"将如何删除除最后一位以外的所有内容，从而仅显示"1"的输出.我知道这行得通，我知道如何从int中获取一点，但是代码如何提取单个位呢?

What I don't understand is how "& 1" will remove everything but the last bit to display an output of simply "1". I know that this works, I know how to get a bit from an int but how is it the code is extracting the single bit?

代码...

int number = 8;
int bit = (number >> 3) & 1;
Console.WriteLine(bit);

推荐答案

除非我从学校毕业的布尔代数使我失败，否则所发生的情况应等同于以下内容:

Unless my boolean algebra from school fails me, what's happening should be equivalent to the following:

              *
  1100110101101  // last bit is 1
& 0000000000001  // & 1
= 0000000000001  // = 1

              *
  1100110101100  // last bit is 0
& 0000000000001  // & 1
= 0000000000000  // = 0

因此，当您执行& 1时，基本上要做的是将所有其他位清零，最后一位将保留原样.或者更确切地说，您是在两个数字之间执行按位AND运算，其中其中一个恰好是1且所有前导位都设置为0

So when you do & 1, what you're basically doing is to zero out all other bits except for the last one which will remain whatever it was. Or more technically speaking you do a bitwise AND operation between two numbers, where one of them happens to be a 1 with all leading bits set to 0

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