相似按位运算符之间的差异 [英] difference between similar bitwise operators

问题描述

在涉及按位运算符时，！和有什么区别?和〜?我觉得他们俩都把这些都弄乱了，但是1可能会在最终答案中加1?

in refereing to bit-wise operators, what is the difference between ! and ~ ? I feel like they both flip the bits, but 1 maybe adds a 1 to the final answer?

~0xC4

compared to

!0xC4

谢谢！

推荐答案

!不是按位运算符，它是布尔运算符.

! is not a bitwise operator, it's a boolean operator.

布尔运算符对真实值(通常为int)进行运算.任何非零值都为true，而0为false.结果始终为1表示true，0表示false.

The boolean operators operate on truth values, which are generally int. Any non-zero value is true, while 0 is false. The result is always 1 for true, 0 for false.

• !不是布尔值
• &&是布尔值，并且
• ||是布尔值或

• ! is boolean not
• && is boolean and
• || is boolean or

这些是例如if，因为它需要一个布尔值.布尔和/或运算符也在短路，这意味着当结果已知时，它们将停止评估.很好，这意味着1 || crash_and_burn()永远不会崩溃和燃烧.

These are the ones used in e.g. if since it needs a boolean value. The boolean and/or operators are also short-circuiting, which means they stop evaluating when the result is known. This is good, it means 1 || crash_and_burn() will never crash and burn.

但是，在提升等之后，按位运算符将对整数型参数的每个位进行运算.

But the bitwise operators operate on each bit of the integer-typed argument(s), after promotions and such of course.

• ~不是按位的
• &是按位的，并且
• |是按位或
• ^是按位或(xor)

• ~ is bitwise not
• & is bitwise and
• | is bitwise or
• ^ is bitwise exlusive-or (xor)

按位运算符(当然)不是短路的，这没有任何意义，因为它们只是对位进行运算.请注意，虽然有一个^按位运算符，但没有^^布尔xor运算符.

The bitwise operators are (of course) not short-circuiting, that wouldn't make any sense since they just operate on pairs of bits. Note that while there is a ^ bitwise operator, there is no ^^ boolean xor operator.

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