需要XSLT转换以删除重复的元素-按属性排序 [英] Need XSLT transform to remove duplicate elements - sorted by an attribute
问题描述
我有一个很糟糕的XML,需要通过BizTalk处理,并且已经设法将其标准化到下面的示例中.我不是XSLT忍者,但在Web和VS2010调试器之间,我可以找到解决XSL的方法.
I have a terrible piece of XML that I need to process through BizTalk, and I have managed to normalise it into this example below. I am no XSLT ninja, but between the web and the VS2010 debugger, I can find my way around XSL.
我现在需要一个聪明的XSLT来清除"重复的元素,并仅保留最新的元素,这取决于 ValidFromDate 属性中的日期.
I now need a clever bit of XSLT to "weed out" the duplicate elements and only keep the latest ones, as decided by the date in the ValidFromDate attribute.
ValidFromDate属性为XSD:Date类型.
The ValidFromDate attribute is of the XSD:Date type.
<SomeData>
<A ValidFromDate="2011-12-01">A_1</A>
<A ValidFromDate="2012-01-19">A_2</A>
<B CalidFromDate="2011-12-03">B_1</B>
<B ValidFromDate="2012-01-17">B_2</B>
<B ValidFromDate="2012-01-19">B_3</B>
<C ValidFromDate="2012-01-20">C_1</C>
<C ValidFromDate="2011-01-20">C_2</C>
</SomeData>
转换后,我只保留以下几行:
After a transformation I'd like to only keep these lines:
<SomeData>
<A ValidFromDate="2012-01-19">A_2</A>
<B ValidFromDate="2012-01-19">B_3</B>
<C ValidFromDate="2012-01-20">C_1</C>
</SomeData>
关于如何将XSL组合在一起的任何线索?我已经清空了互联网,试图寻找解决方案,并且尝试了很多聪明的XSL排序脚本,但是没有一个能带我正确的方向.
Any clues as to how I put that XSL together? I've emptied the internet trying to look for a solution, and I have tried a lot of clever XSL sorting scripts, but none I felt took me in the right direction.
推荐答案
比@lwburk的解决方案更简单,更短的XSLT 1.0解决方案:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:key name="kName" match="*/*" use="name()"/>
<xsl:template match="/">
<xsl:apply-templates select=
"*/*[generate-id()
=
generate-id(key('kName', name())[1])
]
"/>
</xsl:template>
<xsl:template match="*/*">
<xsl:for-each select="key('kName', name())">
<xsl:sort select="@ValidFromDate" order="descending"/>
<xsl:if test="position() = 1">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
当此转换应用于提供的XML文档时:
<SomeData>
<A ValidFromDate="2011-12-01">A_1</A>
<A ValidFromDate="2012-01-19">A_2</A>
<B CalidFromDate="2011-12-03">B_1</B>
<B ValidFromDate="2012-01-17">B_2</B>
<B ValidFromDate="2012-01-19">B_3</B>
<C ValidFromDate="2012-01-20">C_1</C>
<C ValidFromDate="2011-01-20">C_2</C>
</SomeData>
产生了所需的正确结果:
<A ValidFromDate="2012-01-19">A_2</A>
<B ValidFromDate="2012-01-19">B_3</B>
<C ValidFromDate="2012-01-20">C_1</C>
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