mysql_num_rows()期望参数1为资源,字符串在 [英] mysql_num_rows() expects parameter 1 to be resource, string given in

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本文介绍了mysql_num_rows()期望参数1为资源,字符串在的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我已经阅读了许多其他有关此确切问题的话题,但是由于某种原因我无法解决我的问题.确实需要一些帮助.

I have read through many other threads about this exact problem, but i for some reason can not solve my problem. Really need some help.

if (!$username||!$password||!$email)
    echo "Please fill out all fields"; 
 else
 {
    //encrypt password
    $password = md5($password);

    //check if username already taken
    $check = mysql_query("SELECT * FROM Test WHERE username = '$username'");
    if (mysql_num_rows($check)>=1)
       echo "Username already taken";

    else

警告:mysql_num_rows()期望参数1为资源,字符串 在/Users .....

Warning: mysql_num_rows() expects parameter 1 to be resource, string given in /Users.....

if (mysql_num_rows($check)>=1)这行..但是当我在phpmyadmin中运行它时,它会向我返回结果.

if (mysql_num_rows($check)>=1) This line..but when i run it in phpmyadmin, it returns results to me ok.

请帮助

推荐答案

尝试这样:

$query = "SELECT username FROM $this->table WHERE username='$sUser'";
$result = mysql_query($query);  
$num_rows = mysql_num_rows($result); 

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