从字符串中获取常见字符 [英] Get common characters from strings

问题描述

我正在寻找比较两个字符串并能够作为单独的字符串取回的方式:

I'm looking for the way of comparing two strings and being able to get back, as separate strings:

• 所有常见字符，
• 不常见的字符，(所有字符，但没有常见的字符)
• 一个字符串唯一的字符.

示例:

A = "123 ABC"
B = "135 AZ"

thingamajigger(A, B)  # would give all these:

intersect = "13 A"  # (includes space)
exclusion = "2BCZ5"
a_minus_b = "2BC"
b_minus_a = "5Z"

a_minus_b非常简单...但是，如果有一种花哨的单线方式将其拉开，那么我很开放.

a_minus_b is quite simple... but if there's one of those fancy one-liner ways to pull it off, then I'm open.

for i in B:
    A = A.replace(i, "")

这有点像对字符串的布尔操作.

It's a bit like boolean operations on strings.

推荐答案

使用 set :

s = set("123 ABC")
t = set("135 AZ")
intersect = s & t # or s.intersection(t)
exclusion = s ^ t # or s.symmetric_difference(t)
a_minus_b = s - t # or s.difference(t)
b_minus_a = t - s # or t.difference(s)

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