如何使项目仅在Android中的语句布尔值时可见 [英] How to make item visible only if statement boolean in android

问题描述

我有下面的静态常量顶部导航菜单

I have static constant top navigation menu with the following item

<item
    android:id="@+id/action_camera"
    android:enabled="true"
    app:showAsAction="always" />
<item
    android:id="@+id/action_gallery"
    android:enabled="true"
    app:showAsAction="always" />

我有两个类MainActivity和SecondActivity

and I have two class MainActivity and SecondActivity

我想只在条件满足时才显示两个项目

I wanna make both item appear only if condition met

示例:如果用户单击第二个活动，则同时显示两个项目.

Exemple : If user clicked on second Activity display both item.

MainActivity

MainActivity

//action bar menu
 @Override
 public boolean onCreateOptionsMenu(Menu menu) {
     //inflate menu
     getMenuInflater().inflate(R.menu.top_navigation_menu, menu);
     return true;
 }
 //handle actionbar item clicks
 @Override
 public boolean onOptionsItemSelected(MenuItem item) {
     int id = item.getItemId();
     if (id == R.id.action_camera){
         //OpenCamera
     }
     if (id == R.id.action_gallery){
         //OpenGallery
     }
     return super.onOptionsItemSelected(item);
 }

推荐答案

您可以执行以下操作:

 @Override
 public boolean onCreateOptionsMenu(Menu menu) {
     //inflate menu
     getMenuInflater().inflate(R.menu.top_navigation_menu, menu);

    MenuItem action_camera_menu_item = menu.findItem(R.id.action_camera);
    MenuItem action_gallery = menu.findItem(R.id.action_gallery);

    action_camera_menu_item.setVisible(conditionOK);
    action_gallery.setVisible(conditionOK);

    return true;
 }

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