boost python是否支持通过ref或value返回向量的函数? [英] does boost python support a function returning a vector, by ref or value?

问题描述

我是python的新手，我看过boost python，它看起来非常 感人的.但是通过介绍我找不到 在任何示例中，对象的矢量都以python列表/元组的形式返回.

I am new to python, I have looked at boost python, and it looks very impressive. However going through the introduction I can not find any examples where, vector of objects are returned as python list/tuples.

即以这个例子为例，我想公开X类，Cont及其所有功能. 关键位将X的向量或字符串返回给python

i.e Take this example, I want to expose class X, Cont and all its functions. critical bit being return a vector of X's or strings to python

  class X {};

   class Cont {

       .....
       // how can this be exposed using boost python
       const std::vector<X>&  const_ref_x_vec() const { return x_vec_;}
       std::vector<X> value_x_vec() const { return x_vec;}

       const std::vector<std::string>& const_ref_str_vec() const { return str_vec_;}
       std::vector<std::string> value_str_vec() const { return str_vec_; }

       ...
   private:
       std::vector<X> x_vec_;
       std::vector<std::string> str_vec_;
  };

我自己徒劳无功的尝试，试图公开类似的功能 const_ref_x_vec()，value_x_vec()等只会导致编译错误.

My own fruitless attempt at trying to expose the functions like const_ref_x_vec(), value_x_vec(),etc just leads to compile errors.

从谷歌搜索到我还没有看到任何支持返回向量的示例 按价值或参考.使用boost python甚至可能吗? 有什么解决方法吗?在这种情况下我应该使用SWIG吗?

from googling around I have not seen any example that support returning vectors by value or reference. Is this even possible with boost python? are there any workarounds ? should I be using SWIG for this case ?

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推荐答案

Autopulated的原因从本质上讲是正确的，但是代码要复杂得多，而且有必要.

Autopulated's reason was essentially correct, but the code was more complicated then necessary.

vector_indexing_suite 可以为您完成所有工作:

The vector_indexing_suite can do all that work for you:

class_< std::vector<X> >("VectorOfX")
    .def(vector_indexing_suite< std::vector<X> >() )
    ;

还有一个 map_indexing_suite .

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