我如何从一个资源$空回应？ [英] How do I get a null response from a $resource?

问题描述

我如何从一个资源$一个空的反应？

How do I get a null response from a $resource?

我运行这样的：

angular.module("services").factory('Member', function($resource) {
  var Member = $resource('/api/v1/member.json');

  Member.current = Member.get();

  return Member;
});

但服务器与响应：

But the server is responding with:

null

由于用户没有登录。

但是，当我登录的结果我得到这样的：

But when I log the result I get this:

Resource
  0: "n"
  1: "u"
  2: "l"
  3: "l"
  $promise: Object
  $resolved: true
  __proto__: Resource

在哪里，因为我本来预计从字面上空。

推荐答案

$ resource.get 方法，默认情况下，预计JSON响应是一个对象（解析时）。
打电话时 $ resource.get（），结果将是$资源的一个实例。

$resource.get method, by default, expects the JSON response to be an object (when parsed). When calling $resource.get(), the result is going to be an instance of the $resource.

在你的榜样，呼吁 Member.get（{ID：1}）会产生被调用的<$c$c>new会员（） ^源 然后人口^源 （XHR时完成）与解析的JSON响应的特性：

In your example, calling Member.get({id:1}) will produce a $resource instance that is created by calling new Member() ^source and then populated ^source (when XHR is completed) with properties of the parsed JSON response:

shallowClearAndCopy(data, value);

与你的成员实例填充函数的签名如下：

The signature of the function with which your Member instance is populated is as follows:

function shallowClearAndCopy(src, dst) {
  dst = dst || {};

  angular.forEach(dst, function(value, key){
    delete dst[key];
  });

  for (var key in src) {
    if (src.hasOwnProperty(key) && key.charAt(0) !== '$' && key.charAt(1) !== '$') {
      dst[key] = src[key];
    }
  }

  return dst;
}

扫视函数体中，你会发现该功能并不期望的src 参数是在SRC（VAR关键别的什么，只是对象（ ）{... ）。所以，如果你为它提供字符串空的结果将是：

Glancing the function body you will realise that the function does not expect src parameter to be anything else but object (for (var key in src) { ...). So, if you provide it with string "null" the result will be:

{1: "n", 2: "u", 3: "l", ...}

---

ngResource内置支持使用JSON一个REST风格的API作为隐含的数据传送格式，因此，你将不能够使用诸如响应空或任何否则这不是一个有效的JSON。

---

ngResource is built to support a RESTfull API with JSON as an implied data transfer format, hence you won't be able to use responses such as "null" or anything else which isn't a valid JSON.

---

除非

除非你使用的<一个href=\"http://$c$c.angularjs.org/1.2.0/docs/api/ngResource.%24resource\"><$c$c>transformResponse转换空来像 {'空'：真正} 飞：

app.factory('Member', function($resource) {
  var Member = $resource('member.txt', {}, {
    get: {
      method: 'GET',
      isArray: false,
      transformResponse: function(data, headersGetter){
        if(data === 'null'){
          return {null: true};
        }
        return angular.fromJson(data);
      }
    }
  });
  return Member;
});

$scope.member = Member.get({id: 1});
console.log($scope.member); // --> {null: true}

演示

DEMO

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