'stream.ReadTimeout'引发了类型'System.InvalidOperationException'的异常,将照片发送给电报机器人 [英] 'stream.ReadTimeout' threw an exception of type 'System.InvalidOperationException' sending photo to telegram bot
问题描述
我在下面编写了用于将照片发送到我的机器人的代码,但是在我的信息流中,我有两个读写例外,并且我的照片未发送.
I wrote below code for sending a photo to my bot, but in my stream, I have two exceptions for read and write and my photo was not send.
我认为可能是此错误的原因,但我无法解决:
I think maybe the reason was this error, but I couldn't fix it:
stream.ReadTimeout
引发了类型为'System.InvalidOperationException'的异常
stream.ReadTimeout
threw an exception of type 'System.InvalidOperationException'
using (var stream = System.IO.File.Open("a.jpg", FileMode.Open))
{
var fileToSend = new FileToSend("a.jpg", stream);
Task.Run(() => bot.SendPhotoAsync(u.Message.Chat.Id, fileToSend).ConfigureAwait(false));
}
推荐答案
出现此异常的原因可能是您在开始任务后立即Dispose
stream
.
The reason for this exception is probably that you Dispose
the stream
immediatly after starting the task.
当执行离开此块时,using
语句在stream
实例上调用Dispose
.您可以删除此using
语句,或者-如果您的方法已经是async
-您可以简单地await
调用SendPhotoAsync()
.没有理由在Task.Run()
中使用另一个线程:
The using
statement calls Dispose
on the stream
instance when execution leaves this block. You can either remove this using
statement or - if your method already is async
- you may simply await
the call to SendPhotoAsync()
. There is no reason to use another thread with Task.Run()
:
using (var stream = System.IO.File.Open("a.jpg", FileMode.Open))
{
var fileToSend = new FileToSend("a.jpg", stream);
await bot.SendPhotoAsync(u.Message.Chat.Id, fileToSend).ConfigureAwait(false);
}
由编译器为此await
调用创建的状态机要注意,只有在由using
语句返回的Task
之后,才执行using
语句的finally
块(其中将调用stream.Dispose()
). SendPhotoAsync
已完成.
The state-machine created by the compiler for this await
call takes care that the finally
block of the using
statement (where stream.Dispose()
will be called) is executed only after the Task
returned by SendPhotoAsync
has completed.
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