Python无法使用< broadcast>发送广播包。地址 [英] Python can't send a broadcast package with <broadcast> address
问题描述
下一个代码发送广播包(在本地Wireshark中签入):
The next code sends broadcast package (checked in local Wireshark):
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.setsockopt(socket.SOL_SOCKET, socket.SO_BROADCAST, 1)
reqdata = struct.pack('<l', 0x01)
s.sendto( reqdata, ( '192.168.1.255', port ))
但是当我在尖括号中写广播而不是恒定的子网广播时,该包没有被发送:
But when I write "broadcast" in angle brackets instead of constant subnet broadcast, the package is not being sent:
s.sendto( reqdata, ( '<broadcast>', port ))
环境:
ActivePython 2.7.5.6(ActiveState Software Inc.)
基于Python 2.7.5(默认为2013年9月16日,23:16:52)
win32上的
[MSC v.1500 32 bit(Intel)]
ActivePython 2.7.5.6 (ActiveState Software Inc.)
based on Python 2.7.5 (default, Sep 16 2013, 23:16:52)
[MSC v.1500 32 bit (Intel)] on win32"
推荐答案
Python支持'< broadcast>'
,请参见套接字-低级网络接口
Python supports '<broadcast>'
, see socket — Low-level networking interface
但是,您可以获得网络设备的广播掩码使用 ipaddress 包
However, you can get broadcast mask of your network device using ipaddress package
import ipaddress
import socket
netmask = '255.255.255.0' # Netmask is to decode network and host addresses
ip = socket.gethostbyname(socket.gethostname()) # Obtain your IP address
net = ipaddress.IPv4Network(ip + '/' + netmask, False)
broadcast = str(net.broadcast_address)
print('My broadcast address =', broadcast)
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