Java BufferedReader while循环超出范围异常 [英] Java BufferedReader while loop out of bounds exception

问题描述

我正在使用BufferedReader从文本文件读取数据。变量 reg是我要访问的数据字符串中的第四个条目。

I am using BufferedReader to read data from a text file. The variable "reg" is the fourth entry in the string of data that I am trying to access.

我正在获取异常：线程 main中的异常java .lang.ArrayIndexOutOfBoundsException：3

I am getting the exception: "Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 3"

这是我的代码：

package calctest;

import static calctest.CalcTest.reg;
import java.io.*;

public class CalcTest {

    static Integer reg, prov;

public static void main(String[] args) throws Exception{

String readFile = "M:\\MandNDrives\\mwallace\\JAVA for NEMS\\EORModule\\NEMSEORDB.txt";
    BufferedReader br = null;
    String line = "";
    String delim = "[ ]+";

    try {        
        br = new BufferedReader(new FileReader(readFile));
        br.readLine();
        while ((line = br.readLine()) != null) {

            String [] reservoir = line.split(delim);

            reg = Integer.parseInt(reservoir[3]);

            System.out.println(reg);

         }
         }catch (FileNotFoundException e) {
         }catch (IOException e) {

       }    

     }

  }

推荐答案

您的错误有与阅读无关。错误是，存储库（有时）的长度小于4。

Your error has nothing to do with the reading. The error is that reservoir (sometimes) has a length less than 4.

 while ((line = br.readLine()) != null) {
        String [] reservoir = line.split(delim);

        for(String s : reservoir)
            System.out.println(s);  //Post what this outputs for debugging purposes

        if (resivoir.length > 3)
            reg = Integer.parseInt(reservoir[3]);
        else
            reg = ... //do something else...

        System.out.println(reg);

 }

这篇关于Java BufferedReader while循环超出范围异常的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！