从Makefile设置LD_LIBRARY_PATH [英] set LD_LIBRARY_PATH from Makefile

问题描述

如何从Makefile中设置LD_LIBRARY_PATH env变量？

How do I set the LD_LIBRARY_PATH env variable from a Makefile?

我有一些链接到共享库的源代码，而该共享库又链接到另一个共享库（大于1）。用于构建应用程序的Makefile仅知道第一个共享库。

I have some source code that links to a shared library that in turn links to a different shared library (more than 1). The Makefile for building the application only knows about the first shared library.

如果要构建它，则必须指定：
#export LD_LIBRARY_PATH = / path / to / the / shared / libs （用于bash）
，并且工作正常。

If I want to build this, I have to specify: #export LD_LIBRARY_PATH=/path/to/the/shared/libs (for bash) and that works fine.

但是，我想从Makefile本身执行此操作。

However, I would like to do this from the Makefile itself.

推荐答案

是的， export是要使用的正确指令。 此处详细记录了该文档。这与make本身用于将变量传播到子make的机制相同。缺点是您不能选择性地将变量传递给某些命令，而不能传递给其他命令。

Yes, "export" is the correct directive to use. It is documented in detail here. This is the same mechanism as make itself uses to propagate variables to sub-makes. The drawback is that you cannot selectively pass down the variable to some commands and not to others.

我可以想到另外两个选项：

There are two other options I can think of:

• 使用 .EXPORT_ALL_VARIABLES （在某处指定为目标），将所有变量导出到以下环境



• 在命令行上指定：

• Using .EXPORT_ALL_VARIABLES (specify as a target somewhere), causes all variables to be exported to the environment of sub-commands.

• Specify on the command line:

foo:
    EXPORTEDVAR=somevalue gcc $< -o $@

这篇关于从Makefile设置LD_LIBRARY_PATH的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！