将字节数组引用为整数 [英] Reference a byte array as an integer

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本文介绍了将字节数组引用为整数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在Python中,我知道python 3中存在某些可以从现有字节数组创建新整数的方法。但是,我正在寻找一种创建对字节数组作为整数的引用的方法。这样,如果引用被更改,则基础字节数组也将更改。

In Python, I am aware certain methods exist in python 3 that can create a new integer from an existing byte array. However, I am looking for a way to create a reference to a byte array, as an integer. Such that, if the reference is changed, then the underlying byte array is also changed.

在C中,这将如下所示:

In C, this would be done like the following:

int main(void) {
  unsigned char bytes[4] = {1, 0, 0, 0};
  int* int_ref = (int*)bytes;
  *int_ref += 59;
  printf("bytes is now %u %u %u %u\n",
                        bytes[0],
                        bytes[1],
                        bytes[2],
                        bytes[3]);
  return 0;
}

以上程序显示 60 。我正在寻找一种在Python中执行此操作的方法。

The above program prints 60. I am looking for a way to do this in Python.

推荐答案

类似的东西似乎与您想要的东西相似:

Something along these lines seems close to what you want:

import _ctypes

def di(obj_id):
    """ Reverse of id() function. """
    # from https://stackoverflow.com/a/15012814/355230
    return _ctypes.PyObj_FromPtr(obj_id)

def func(obj_id):
    ba = di(obj_id)
    ba[0] += 50

data = bytearray([1, 0, 0, 0])
func(id(data))

print('bytes is now {} {} {} {}'.format(*data))  # -> bytes is now 51 0 0 0

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