如何在C中将二进制数组转换为十六进制 [英] How to convert binary array into a hexadecimal in C

问题描述

因此，目前我有一个二进制数字数组，例如{1，1，1，1，0，0，0，0}，我试图弄清楚如何将这个数组转换为十六进制数字在C中键入 uint8_t（在此示例中，我希望它为0xf0），但我一直在努力寻找方法。到目前为止，我已经可以将数字转换为十六进制字符串，但我希望它是无符号整数类型。有人可以给我一些建议吗？谢谢！

So currently I have an array of binary digits, say {1, 1, 1, 1, 0, 0, 0, 0} and I'm trying to figure out how I can convert this array into a hexadecimal digit of type 'uint8_t' in C (in this example, I would want it to be 0xf0) except I'm struggling to figure out how to do so. So far I've been able to convert the digit to hexadecimal string except I want it to be an unsigned integer type. Could anyone please provide me some suggestions? Thank you!

推荐答案

尝试一下

#include <stdio.h>
#include <stdint.h>

uint16_t ConvertToDec(uint16_t* bits, uint16_t size)
{
    uint16_t result = 0;

    for (uint16_t i = 0; i < size; i++) {

        result |= bits[i];
        if(i != size-1)
            result <<= 1;
    }

    return result;

}

int main()
{
    uint16_t bits[] = { 1, 1, 1, 1, 0, 0, 0, 0 };
    uint16_t len = (sizeof(bits) / sizeof(bits[0])); // get array size
    uint16_t result = ConvertToDec(bits, len);
    char hex[20];
    sprintf(hex, "0x%02X", result);
    printf("%s", hex);

    return 0;
}

ConvertToDec将数组转换为8位数字，并使用sprintf将输出保存为十六进制到十六进制缓冲区中。
编辑：我对代码进行了一些修改，使其更具可读性，并且还可以使用16位数字。

ConvertToDec converts the array into 8 bit number, and using sprintf saves the output as hex into the hex buffer. Edit : I have modified the code a little bit making it more readable and also to work with 16 bit numbers as well.

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