从数组中删除项目的所有实例 [英] Removing all instances of items from array

问题描述

我有一个可能有重复值的数组

I have an array which may have duplicate values

$array1 = [value19, value16, value17, value16, value16]

我正在寻找一个高效的PHP小函数，可以接受数组或字符串（无论哪个

I'm looking for an efficient little PHP function that could accept either an array or a string (whichever makes it easier)

$array2 = ["value1", "value16", "value17"];
or 
$string2 = "value1 value16 value17";

并从array1删除array2或string2中的每个项目。

and removes each item in array2 or string2 from array1.

此示例的正确输出为：

$array1 = [value19]

对于那些有PHP经验的人来说，

For those more experienced with PHP, is something like this available in PHP?

推荐答案

，您正在寻找 array_diff

$array1 = array('19','16','17','16','16');
$array2 = array('1','16','17');
print_r(array_diff($array1,$array2));

数组（[0] => 19）

Array ( [0] => 19 )

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