$ q.all和嵌套的承诺 [英] $q.all and nested promises

问题描述

有一个关于使用角$ Q时同步嵌套的承诺的问题。
将以下code确保承诺的整个链条中等待？这意味着将要返回的诺言等待在$ q.all阻止？业务的嵌套调用

Have a question about synchronizing nested promises when using $q in Angular. Will the following code ensure that the entire chain of promises is waited for? Meaning will the nested calls to services that return promises be waited for in the $q.all block?

var call1 = service1.get('/someUr').then(function(){
  return service2.get('/someUrl2'); //returns promise
});

var call2 = service3.get('/someUr').then(function(){
  return 'hello';
});

var call3 = service4.get('/someUr').then(function(){
  return service3.get('/someUrl3');//returns promise
});

$q.all(call1,call2,call3).then(function(){
  console.log('All asynch operations are now completed');
});

基本上是：是否有与当前code一个机会，当时的$ q.all所有嵌套之前承诺将执行都解决了？抑或是递归的？

Basically: Is there a chance with the current code that the then of $q.all will execute before all the nested promises are resolved? Or is it recursive?

推荐答案

是的，它看起来像凯文是正确的。我在角创建了一个简单的测试，以及确认行为。

Yes it looks like Kevin is correct. I created a quick test in angular as well to confirm the behavior.

angular.module('myModule').controller('testController', function ($q,$scope) {

  function promiseCall(data,timeout) {
    var deferred = $q.defer();

    setTimeout(function() {
      deferred.resolve(data);
      console.log(data);
    }, timeout);

    return deferred.promise;
  }

  var a = promiseCall('call1 a',1000).then(function(){
    return promiseCall('call2 a',50);
  });

  var b = promiseCall('call1 b',500);

  var c = promiseCall('call1 c',1000).then(function(){
    return promiseCall('call2 c',50).then(function(){
      return promiseCall('call3 c',6000);
    });
  });

  $q.all([a,b,c]).then(function(res){
    console.log('all calls are done');
  });

});

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