在Powershell中是否可以将字节数组转换为8位有符号整数数组？ [英] Is it possible to convert a byte array to a 8-bit signed integer array in Powershell?

问题描述

我正在尝试在Powershell中将十六进制字符串转换为8位带符号整数数组。

I am trying to convert a Hex string to an 8-bit signed integer array in Powershell.

我正在使用以下函数将十六进制字符串（例如A591BF86E5D7D9837EE7ACC569C4B59B）转换为字节数组，然后需要将其转换为8位带符号整数数组。

I am using the following function to convert a Hex string, such as A591BF86E5D7D9837EE7ACC569C4B59B, to a byte array which I then need to convert to a 8-bit signed integer array.

Function GetByteArray {

    [cmdletbinding()]

    param(
        [parameter(Mandatory=$true)]
        [String]
        $HexString
    )

    $Bytes = [byte[]]::new($HexString.Length / 2)

    For($i=0; $i -lt $HexString.Length; $i+=2){
        $Bytes[$i/2] = [convert]::ToByte($HexString.Substring($i, 2), 16)
    }

    $Bytes  
}

使用该函数后，十六进制将转换为字节数组，如下所示：

After using the function the hex is converted to a byte array such as this:

我需要获取无符号字节数组并将o转换为8bit带符号的字节数组，如下所示：

I need to take the unsigned byte array and convert o to 8bit signed byte array, like the one below:

这可能吗？如果可以，如何实施？

Is this possible? If so how can it be implemented?

我尝试使用BitConverter类，但据我所知，它只能转换为int16。

I've tried using the BitConverter class but, as far as I saw, it can only convert to int16.

预先感谢

推荐答案

获得 [byte []] 数组（ [byte] == System.Byte ， unsigned 8位整数类型）：

To get a [byte[]] array ([byte] == System.Byte, an unsigned 8-bit integer type):

$hexStr = 'A591BF86E5D7D9837EE7ACC569C4B59B' # sample input

[byte[]] ($hexStr -split '(.{2})' -ne '' -replace '^', '0X')

• -split'（。{2}）'用2个字符分割输入字符串序列，并用（...）括起来会导致这些序列包含在返回的令牌中； -ne''然后清除 empty 令牌（从技术上讲是实际的数据令牌）。

  • -split '(.{2})' splits the input string by 2-character sequences, and enclosure in (...) causes these sequences to be included in the returned tokens; -ne '' then weeds out the empty tokens (which are technically the actual data tokens).

    -replace，'^'，'0X'将前缀 0X 放在每个结果之前2个十六进制数字的字符串，产生数组'0XA5'，'0X91'，...

    -replace , '^', '0X' places prefix 0X before each resulting 2-hex-digit string, yielding array '0XA5', '0X91', ...

    将结果投射到 [byte []] 有助于直接识别此十六进制格式。

    casting the result to [byte[]] helpfully recognizes this hex format directly.

    
    
    • 注意：如果您忘记了转换，则会得到一个 strings 数组。
    
    
    • Note: If you forget the cast, you'll get an array of strings.

    要获取 [sbyte []] 数组（ [sbyte] == 系统.SByte ，一个 signed 8位整数），直接将投射到 [sbyte []] 代替； not 尝试组合强制转换： [sbyte []] [byte []]（...） ）

    To get an [sbyte[]] array ([sbyte] == System.SByte, a signed 8-bit integer), cast directly to [sbyte[]] instead; do not try to combine the casts: [sbyte[]] [byte[]] (...))

    如果您 已获 然后要转换为 [sbyte []] [byte []] 数组> ，请使用以下方法（可能有更有效的方法）：

    If you're given a [byte[]] array that you then want to convert to [sbyte[]], use the following (there may be more efficient approaches):

    [byte[]] $bytes = 0x41, 0xFF # sample input; decimal: 65, 255
    
    # -> [sbyte] values of:  65, -1
    [sbyte[]] $sBytes = ($bytes.ForEach('ToString', 'X') -replace '^', '0X')
    

    应用于样本值，以十进制表示：

    Applied to your sample values, in decimal notation:

    # Input array of [byte]s.
    [byte[]] $bytes = 43, 240, 82, 109, 185, 46, 111, 8, 164, 74, 164, 172
    # Convert to an [sbyte] array.
    [sbyte[]] $sBytes = ($bytes.ForEach('ToString', 'X') -replace '^', '0X')
    $sBytes # Output (each signed byte prints on its own line, in decimal form).
    

    输出：

    43
    -16
    82
    109
    -71
    46
    111
    8
    -92
    74
    -92
    -84
    

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