将JSON数组数据分组并计数是否具有两个相同的值 [英] Group JSON array data and count it if have two same value

问题描述

下面的Json需要按 kecamatan 分组，以获取 desa 的数组以及kecamatan是否具有相同数组值的计数。

Following Json needs to group by kecamatan to get array of desa along with count if kecamatan have same array value.

{
"data": [
        {
            "ID": 47,
            "kecamatan": "Benteng",
            "desa": "Benteng Selatan"
        },
        {
            "ID": 48,
            "kecamatan": "Benteng",
            "desa": "Benteng Selatan"
        },
        {
           "ID": 49,
            "kecamatan": "Benteng",
            "desa": "Benteng Utara"
        },
        {
            "ID": 50,
            "kecamatan": "Bontomantene",
            "desa": "Garaupa"
        }
    ]
}

预期输出：-

• Benteng [Benteng selatan] = 2


• Benteng [Benteng Utara] = 1
  
• Bontomantene [Garaupa] = 1

推荐答案

请尝试

private void jsonObject() {
    String result =  "{\"data\": [{\"ID\": 47,\"kecamatan\": \"Benteng\",\"desa\": \"Benteng Selatan\"},{\"ID\": 48,\"kecamatan\": \"Benteng\",\"desa\": \"Benteng Selatan\"},{\"ID\": 49,\"kecamatan\": \"Benteng\",\"desa\": \"Benteng Utara\" },{\"ID\": 50,\"kecamatan\": \"Bontomantene\",\"desa\": \"Garaupa\"}]}";
    try {
        JSONObject jsonObject = new JSONObject(result);
        HashMap<String,Integer> hashMap = new HashMap<>();
        for (int i=0;i<jsonObject.getJSONArray("data").length();i++){
            JSONObject innerJsonObject = jsonObject.getJSONArray("data").getJSONObject(i);
            String key = innerJsonObject.getString("kecamatan")+" ["+innerJsonObject.getString("desa")+"]";
            if(hashMap.containsKey(key)){
                int count = hashMap.get(key)+1;
                hashMap.put(key,count);
            }else {
                hashMap.put(key,1);
            }
        }
        Log.e("Hashmap---",hashMap.toString());
    } catch (JSONException e) {
        e.printStackTrace();
    }
}

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