python:生成间距不均匀的数组 [英] python: generate unevenly spaced array
问题描述
我想生成一个由下限值和上限值限制的数组,该数组具有n个元素,类似于:
I would like to generate an array bounded by a lower and upper value with n elements similar to:
def my_lin(lb, ub, steps):
dx = (ub-lb) / (steps-1)
return [lb + i*dx for i in range(steps)]
my_lin(0,10,11)
但我希望更多的值更接近较低的值值。某种谐波间隔。我不想有一个对数间距。
But I would like to have more values closer to the lower value. Some kind of harmonic spacing. I do not want to have a logarithmic spacing.
我想这很简单,但我无法弄清楚。非常感谢您的帮助。
I guess it is rather simple but I cannot figure it out. Any help is highly appreciated.
编辑:
我想出了以下快速解决方案:
I came up with following quick solution:
def harm_series(lb,n):
return [float(lb)/float(i) for i in range(1,n) ]
推荐答案
查找函数 f
,它在 [0,1]
内具有您想要的间距(请注意 f(0)== 0和f(1)== 1
应该保留),然后应用 f(i * dx /(ub-lb))*(ub-lb)
。
Find a function f
which has your desired spacing within [0,1]
(note that f(0)==0 and f(1)==1
should hold) and then apply f(i*dx/(ub-lb))*(ub-lb)
.
我个人喜欢此功能,但还有更多功能。
例如,尝试以下操作:
I personally like power functions for this but there is many more. For example, try this:
def my_lin(lb, ub, steps, spacing=1.1):
span = (ub-lb)
dx = 1.0 / (steps-1)
return [lb + (i*dx)**spacing*span for i in range(steps)]
lin = my_lin(0, 10, 11)
print lin
# visualize the spacing
print ''.join(' '*int(2*a)+'*' for a in lin)
打印:
[0.0, 0.7943282347242814, 1.702679845041569, 2.6597044516956405, 3.6497741462219233, 4.665164957684037, 5.701201299034059, 6.754727665838724, 7.823462148343428, 8.905673323855929, 10.0]
* * * * * * * * * * *
现在使用参数 spacing
可以正常工作像这样:
Now with the parameter spacing
it works like this:
- 离零越近,您在
ub $ c $周围收集的值就越多c>
- 从1到另一个方向越远,mo它们是否聚集在
lb
- 如果
spacing
正好为1,则它们是等距
- The closer you get to zero, the more your values gather around
ub
- The farther you go away from 1 into the other direction, the more they gather around
lb
- If
spacing
is exactly 1, they are equally spaced
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