验证数组的最后一个值是否大于先前的值 [英] Validate if the last value of array is greater than previous value

问题描述

我有一个值为 [0,3,4,6,0] 的数组，如何验证前值是否小于后值？

I have an array with value, [0,3,4,6,0], How do I validate if the before values is less than the after values?

var array = [0,3,4,6,0];
for(var i = 0; i < array.length; i++){
   //if the value of 0 >,3 >,4, > 6
   //return false;
}

我需要要求用户输入一个有序的数字序列，例如 5、4、3、2、1 。因此，我需要验证输入是否不按顺序排列。

I need to require the user to enter an ordered sequence of numbers like 5, 4, 3, 2, 1. Hence, I need to validate if the enter is not in an ordered sequence.

推荐答案

在ES5中使用 Array＃every

function customValidate(array) {
  var length = array.length;
  return array.every(function(value, index) {
    var nextIndex = index + 1;
    return nextIndex < length ? value <= array[nextIndex] : true;
  });
}
console.log(customValidate([1, 2, 3, 4, 5]));
console.log(customValidate([5, 4, 3, 2, 1]));
console.log(customValidate([0, 0, 0, 4, 5]));
console.log(customValidate([0, 0, 0, 2, 1]));

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