计算数组中当前元素右侧的更大元素 [英] Count greater elements on right side of a current element in an array

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问题描述

我正在尝试计算大于数组右侧元素的元素数。

I am trying to count the number of elements greater than the element on the right side of the array. Here my function goes.

int* SurpassersKing(int input1_size, int* input1,int* output_size)
    {
        int i,k;
        int count[input1_size];
        for  (i = 0; i < input1_size; i++)
            count[i] = 0;


        for ( i = 0; i < input1_size; i++) 
        {
            for ( k = i + 1; k <input1_size; k++) 
                {
                        if (input1[i] < input1[k]) {
                                 count[i]++;
                        }
                }
        } 

        return count;
    }

这是我在函数中计算数组中更大元素的函数。

This is my function where I am counting greater elements in an array.

因此,在下面的代码段中,我编写了main函数,声明了所有像veriable一样的output_size,counting array,i,k作为数组的索引并打印了东西,并调用计数函数。

So in this following code snippet i have wriiten the main function , declaring all the veriable like output_size,counting array ,i ,k as an index for the arrays and printing the stuff , and calling counting function .

int main() {
    int output_size;
    int* output;

    int ip1_size = 0;
    int ip1_i;
    scanf("%d\n", &ip1_size);
    int ip1[ip1_size];
    for(ip1_i = 0; ip1_i < ip1_size; ip1_i++) {
        int ip1_item;
        scanf("%d", &ip1_item);

        ip1[ip1_i] = ip1_item;
    }
    output = SurpassersKing(ip1_size,ip1,&output_size);
    int output_i;
    for(output_i=0; output_i < output_size; output_i++) {

        printf("%d\n", output[output_i]);

    }
    return 0;
}

但是我没有得到所需的输出,所以我该怎么做才能改善这一点

but i am not getting the output required so what can i do to improve this.

推荐答案

因此,您的代码在尝试编译时发现了一些错误。

Oso your code has a few errors i found when i tried to compile.


  1. 这是交流代码,因此请在函数SurpassersKing中使用#include

  1. This is a c code so use #include

返回不允许的数组计数。除非它是动态创建的,否则切勿返回局部变量。

Inside the function SurpassersKing you are trying to return array count which is not allowed. Never return local variables unless it is dynamically created.

output_size不会初始化。

The output_size never gets initilized.

这是最终代码:

#include <stdio.h>
#include<stdlib.h>

int* SurpassersKing(int input1_size, int* input1)
{
    int i,k;
    int * count = (int*)malloc(input1_size*sizeof(int));
    for  (i = 0; i < input1_size; i++)
        *(count + i) = 0;


    for ( i = 0; i < input1_size; i++) 
    {
        for ( k = i + 1; k <input1_size; k++) 
            {
                    if (input1[i] < input1[k]) {
                             count[i]++;
                    }
            }
    } 

    return count;
}

int main() {
// your code goes here
int output_size;
int* output;

int ip1_size = 0;
int ip1_i;
int output_i;

printf("Enter the size:\n");
scanf("%d",&ip1_size);
int ip1[ip1_size];
for(ip1_i = 0; ip1_i < ip1_size; ip1_i++) {
    scanf("%d",%ip1[ip1_i]);
}
output = SurpassersKing(ip1_size,ip1);
output_size = ip1_size;

for(output_i=0; output_i < output_size; output_i++) {

    printf("%d\n",output[output_i]");

}
return 0;
}

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