数组在最后发送空值并重新排列数组 [英] Array to send empty value at last and rearrange array

问题描述

我有一个数组。

如果之间的任何数组值变为空或null，我希望该空值之后的任何值都可以在该空数组中移动。

If any array values within between becomes empty or null I want any after that empty value to be shifted within that empty array.

我通过取消设置数组使用了foreach循环，但问题是，如果存在0值，则该数字大于0则排在第二位，然后大于0则移位在第一名。

I used a foreach loop by unsetting an array but the problem is that if there is a 0 value the number greater then 0 shifts at second place and greater then 0 values shifts at 1st place.

我不知道这是怎么回事。

I do not know how come this is happening.

这是我的代码：

$val1     = $this->input->post('current');
$val2     = $this->input->post('graph1');
$val3     = $this->input->post('graph2');
$val4     = $this->input->post('graph3');
$val5     = $this->input->post('graph4');
$filter   = array($val1, $val2, $val3, $val4, $val5);
//array(0, '', 2, '', '')
foreach ($filter as $key => $value) { 
    if (empty($value)) { 
        unset($filter[$key]);
        $filter[] = $value;
    }
}

$filter_new = array_values($filter);
//array(2, 0, '', '', '') 

推荐答案

您的问题是 empty（0）返回 TRUE ，因此如果您的 0 值传递到第二个位置。

Your problem is empty(0) returns TRUE, so it's normal if your 0 value pass on 2nd position.

尝试一下：

    foreach ($filter as $key => $value) { 
        if ($value == '') { 
            unset($filter[$key]);
            $filter[] = $value;
        }
    }

    $filter_new = array_values($filter);
    //array(0, 2, '', '', '') 

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