Python和排序：按元素在数组中的子元素排序 [英] Python & Sorting : Sorting Elements In Order Their Subelements in an Array

问题描述

我有一个数组，它有4个元素，每个元素都有3个子元素；

I have an array and it has 4 elements and every element has 3 subelements;

myList = [['26.03.2019', 'Michelle', '8'], ['03.04.2019', 'Jack', '2'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8']]

如您所见，每个元素的第一个子元素都是日期。我想订购这些元素及其日期。所以当我输入 print（myList）;

As you see, every elements' first subelement is a date. And I want to order these elements with their dates. So I want that output when I enter print(myList);

[['26.03.2019', 'Michelle', '8'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8'], ['03.04.2019', 'Jack', '2']]

我该怎么做？

推荐答案

print（myList）只会打印您的列表。您不想摆弄。您要做的是在打印前对列表进行排序。例如，例如：

print(myList) would just print your list. You do not want to fiddle with that. What you want to do is sort your list prior to printing. Like so for example:

import datetime


myList = [['26.03.2019', 'Michelle', '8'], ['03.04.2019', 'Jack', '2'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8']]
myList.sort(key=lambda sublist: datetime.datetime.strptime(sublist[0], "%d.%m.%Y"))

print(myList)  # -> [['26.03.2019', 'Michelle', '8'], 
               #     ['01.04.2019', 'George', '2'], 
               #     ['02.04.2019', 'Micheal', '8'], 
               #     ['03.04.2019', 'Jack', '2']]

请注意，执行 myList.sort（..）会永久更改您的列表。如果这不是您想要的，则可以创建一个新的使用@Rakesh在他的答案中建议的排序。

Note that doing myList.sort(..) permanently changes your list.. If that is not what you want, you can create a new one using sorted as @Rakesh proposes in his answer.

荣誉：用于日期排序的代码来自此处

Kudos: the code for the sorting of the dates was taken from here

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