PHP-如何部分比较2个数组中的元素 [英] PHP - How do I partially compare elements in 2 arrays

问题描述

我有2个数组：

$arr1 = array('Test', 'Hello', 'World', 'Foo', 'Bar1', 'Bar'); and
$arr2 = array('hello', 'Else', 'World', 'Tes', 'foo', 'BaR1', 'Bar'); 

我需要比较2个数组并将匹配元素的位置保存到第3个数组 $ arr3 =（3，0，2，4，4，5，6）; //期望的结果，显示$ arr1的匹配元素在$ arr2中的位置。

I need to compare the 2 arrays and save the position of the matching elements to a 3rd array $arr3 = (3, 0, 2, 4, 5, 6); //expected result, displaying position of matching element of $arr1 in $arr2.

匹配是指所有相同的元素（例如世界），或部分相同（例如Test& Tes），以及那些相似但大小写不同的元素（例如Foo& foo，Bar& bar）。

By 'matching' I mean all elements that are identical (ex. World), or partially the same (ex. Test & Tes) and also those elements that are alike but are in different case (ex. Foo & foo, Bar & bar).

我已经尝试了一系列组合和各种功能，但均未成功，使用了 array_intersect（），substr_compare（），array_filter（）及更多。我不是要确切的解决方案，只是要让我走上正轨，因为我整个下午都在兜圈子。

I've tried a series of combinations and of various functions without success, using functions like array_intersect(), substr_compare(), array_filter() and more. I'm not asking for the exact solution, just something to get me on the right track because i'm going around in circles all afternoon.

推荐答案

这似乎对我有用，但是我确定我缺少一些极端的情况，因此您需要测试以下内容：

This seemed to work for me, but I'm sure there are some edge cases I'm missing that you'd need to test for:

foreach( $arr1 as $i => $val1) {
    $result = null;
    // Search the second array for an exact match, if found
    if( ($found = array_search( $val1, $arr2, true)) !== false) {
            $result = $found; 
    } else {
        // Otherwise, see if we can find a case-insensitive matching string where  the element from $arr2 is at the 0th location in the one from $arr1
        foreach( $arr2 as $j => $val2) {            
            if( stripos( $val1, $val2) === 0) {
                $result = $j;
                break;
            }
        }
    }
    $arr3[$i] = $result;
}

它产生所需的输出数组：

Array ( [0] => 3 [1] => 0 [2] => 2 [3] => 4 [4] => 5 [5] => 6 )  

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