PHP数组，输出，仅在type ='image / jpeg'时输出 [英] PHP array, output, output only where type = 'image/jpeg'

问题描述

我有php数组（$ _FILE [失败]）我只需要输出类型为 image / jpeg或 image / jpg的名称...

I have php array ($_FILE[fails]) I need to output only thous names where type is "image/jpeg" or "image/jpg" ...

array(5) { ["name"]=> array(4) { [0]=> string(16) "3970867_460s.jpg" [1]=> string(12) "DSCI0783.JPG" [2]=> string(8) "dump.php" [3]=> string(0) "" } 
           ["type"]=> array(4) { [0]=> string(10) "image/jpeg" [1]=> string(10) "image/jpeg" [2]=> string(24) "application/octet-stream" [3]=> string(0) "" } 
           ["tmp_name"]=> array(4) { [0]=> string(27) "C:\Windows\Temp\phpC9C9.tmp" [1]=> string(27) "C:\Windows\Temp\phpC9DA.tmp" [2]=> string(27) "C:\Windows\Temp\phpC9DB.tmp" [3]=> string(0) "" } 
           ["error"]=> array(4) { [0]=> int(0) [1]=> int(0) [2]=> int(0) [3]=> int(4) } ["size"]=> array(4) { [0]=> int(101011) [1]=> int(55354) [2]=> int(12290) [3]=> int(0) } 
         }

该怎么做？
和foreach？

How to do it? with foreach?

foreach ($_FILES["fails"] as $x => $y ) {
echo $y->....something here?
   if(($y->... == 'image/jpeg') AND (..)) {}
} 

谢谢！

推荐答案

for ($i = 0; $i < count($_FILES['fails']['name']); $i++) {
    if ($_FILES['fails']['type'][$i] == "image/jpeg" || $_FILES['fails']['type'][$i] == "image/jpg") {
        echo "Name : " . $_FILES['fails']['name'][$i];
        echo "Type : " . $_FILES['fails']['type'][$i];
    }
}

这将回显每个图像的名称和类型/数组中的jpg或图像/ jpeg。

This will echo the name and type of every image/jpg or image/jpeg in the array.

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