如果任何元素为空，则删除数组 [英] Remove array if any element is empty

问题描述

我的数组具有以下结构。它是通过表单提交的文件数组。我有多个表单输入字段。但是，如果用户将某些字段留空，则该数组将显示如下。
然后将其写入数据库。我不想写空字段。

My array is of following structure. It is a array of files submitted through form. I have multiple input fields for form. However if the user leave some field blank, the array will be displayed like below. I am then writing it to my database. I dont want the empty fields to be written.

我尝试使用 array_filter（）函数，但不会工作，因为我的数组不是完全为空。错误元素设置为 4 。我该怎么做？

I tried using array_filter() function, but it will not work since my array is not completely empty. The error element is set to 4. How do i do it?

Array
(
    [0] => Array
        (
            [name] => stock-photo-cup-icons-tea-and-coffee-raster-version-109119257.jpg
            [type] => image/jpeg
            [tmp_name] => /tmp/phpqWWM9X
            [error] => 0
            [size] => 30609
        )

    [1] => Array
        (
            [name] => 
            [type] => 
            [tmp_name] => 
            [error] => 4
            [size] => 0
        )

    [2] => Array
        (
            [name] => 
            [type] => 
            [tmp_name] => 
            [error] => 4
            [size] => 0
        )

    [3] => Array
        (
            [name] => 
            [type] => 
            [tmp_name] => 
            [error] => 4
            [size] => 0
        )

)

推荐答案

您可以将（可选）回调传递给 array_filter（） ：

You can pass an (optional) callback to array_filter():

$filteredArray = array_filter($source, function($item) {
    return ($item['size'] > 0 && $item['error'] === 0);
});

var_dump($filteredArray);

演示： http://codepad.viper-7.com/uocPT6

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