数组输入似乎只接受最后一个输入 [英] Array input only seems to take the last input

问题描述

 导入java.util.Scanner; 
 import java.util.Arrays; 
 
公共类Sort_Array {
 
 public static void main（String [] args）{
 
 int a; 
 
 Scanner sc = new Scanner（System.in）; 
 
 System.out.println（输入数组大小）; 
 int n = sc.nextInt（）; 
 
 int [] arr_num = new int [n]; 
 
 System.out.println（在数组中输入整数）; 
 
 for（int i：arr_num）
 {
 arr_num [i] = sc.nextInt（）; 
} 
 
 System.out.println（排序前的数组---- \n）; 
 
 for（int j：arr_num）
 {
 System.out.print（j +，）; 
} 
 System.out.println（ \n）; 
 
 Arrays.sort（arr_num）; 
 
 System.out.println（排序后的数组---- \n）; 
 
 for（int k：arr_num）
 {
 System.out.print（k +，）; 
} 
} 
} 
  

输出

 输入数组的大小
 2 
输入整数数组
 5 
 6 
排序前的数组---- 
 
 6,0，
 
排序后的数组---- 
 
 0,6，
  

解决方案

  System.out.println（输入数组大小）; 
 int n = sc.nextInt（）; 
 
 int [] arr_num = new int [n]; 
  

在这里，您可以看到经过数组大小即2时的实际情况。 p>

arr_num初始化为0值（这是int对象的默认值）

  0 0 
  

此后，您对每个都使用了 >循环。
基本上说，当您看到冒号（:)时，将其读为 in。因此，基本上，您正在读取array_num中每个为0 0的int i。

  for（int i：arr_num ）
 {
 arr_num [i] = sc.nextInt（）; // arr_num [0] = sc.nextInt（）; 
 //再次，arr_num [0] = sc.nextInt（）; 
} 
  

所以这就是你得到的原因

  6,0 
  

因为<您输入的em> 5 现在在arr_num [0]处再次由 6 代替。而第二个0仍然停留在arr_num [1]。

如其他答案所示，请使用其他循环。并了解有关每个循环的更多信息。

import java.util.Scanner;
import java.util.Arrays;

public class Sort_Array {

    public static void main(String[] args) {

        int a;

        Scanner sc = new Scanner(System.in);

        System.out.println(" Enter size of Array ");
        int n = sc.nextInt();

        int[] arr_num = new int[n];

        System.out.println(" Enter the integers in the Array");

        for(int i : arr_num)
        {
            arr_num[i] = sc.nextInt();
        }

        System.out.println(" Array before sorting ----\n");

        for(int j : arr_num)
        {
            System.out.print(j+",");
        }
        System.out.println("\n");

        Arrays.sort(arr_num);

        System.out.println(" Array after sorting ----\n");

        for(int k : arr_num)
        {
            System.out.print(k+",");
        }
    }
}

Output

 Enter size of Array 
2
 Enter the integers in the Array
5
6
 Array before sorting ----

6,0,

 Array after sorting ----

0,6,

解决方案

 System.out.println(" Enter size of Array ");
    int n = sc.nextInt();

    int[] arr_num = new int[n];

Here you see what is really happening when you have passed the size of the array say, 2

arr_num is getting initialized with 0 value ( which is the default value for int object)

0 0

After this, you have used the for each loop. Which basically says, When you see the colon (:) read it as "in." So basically, you are reading each int i in array_num which are 0 0.

for(int i : arr_num)
    {
        arr_num[i] = sc.nextInt();    //arr_num[0] = sc.nextInt();
                                      //again, arr_num[0] = sc.nextInt();
    }

So this is the reason you are getting

 6,0 

because 5 which was inputted by you is now replaced by 6 again at arr_num[0]. while 2nd 0 still stays which is at arr_num[1].

As other answers suggest, use a different loop. And read more about for each loop.

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