Java数字随机数组 [英] Java random array of numbers

问题描述

我正在尝试制作一个范围为0-9的随机数数组，其中一个变量是kickerNumbers。我说不兼容的类型，但出现编译错误。我曾尝试将（int）更改为 [int] ，但我不认为那会是无论如何，而且事实并非如此。还有另一种写方法吗？我需要它充当前4个数字，以0-9表示，但第5个数字必须较小，例如0-4。对于0-4，我只是做了一个完全不同的变量。那是一个好选择吗？这是给出错误的行的示例代码。

I am trying to make an array of random numbers that range from 0-9 with the variable for this one being kickerNumbers. I get a compile error though saying incompatible types. I have tried changing the (int) to [int] like it said but I didn't think that would be right anyway and surly enough it wasn't. Is there another way to write this? I need it to act as the first four numbers of this to be 0-9 but the fifth number would need to be something smaller such as 0-4. for the 0-4 one I just made that a completely different variable. Was that a good choice? Here is the sample code for the lines that give the error.

import java.util.Scanner;
import java.util.InputMismatchException;
public class CashBallTest
{
    public static void main(String[]args)
    {
        Scanner keyboard = new Scanner(System.in);
        int kicker;
        int[] kickerNumbers = (int)(Math.random()*0+9);
        int kickerPowerball=(int)(Math.random()*0+4);

错误为：

\CashBallTest.java:9: incompatible types
    found   : int
    required: int[]
    int[] kickerNumbers = (int)(Math.random()*0+9);

我也尝试过更改（int）到（int []），但随后它表示它是不可转换的类型，当它需要是 int [] ，但我看不到它从何处获取双精度类型。

I have also tried changing (int) to (int[]) but then it said it was an inconvertible type counting as a double when it needs to be an int[] but I don't see where it gets the double type from.

推荐答案

int[] kickerNumbers = (int)(Math.random()*0+9);

您不能将 int 分配给 int []

假设应该更多的是一个数字，可能是这样的

Assuming that is supposed to be more the one number, it might be something like this

int[] kickerNumbers = new int[5];
for(int i = 0; i < kickerNumbers.length; i++) {
    kickerNumbers[i] = (int)(Math.random()*0+9);
}

在不相关的音符上，为什么要乘以 Math.random（）* 0 ？这对我来说似乎很愚蠢。如果您想要一个1到10的数字，我可以这样做： Math.random（）* 10 + 1

On an unrelated note, why are you multiplying the Math.random()*0? That seems silly to me. If you want a number 1 through 10, I would do this: Math.random()*10 + 1

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