将项目添加到一个数组之后的另一个数组中的每个项目之后 [英] Add items to one array after each item on another array

问题描述

基本上，我需要在一个数组中的每个元素之后添加另一个数组中的每个元素。因此，如果这是两个数组：

Basically I need to add each item from one array after each on from another array. So if these are the two arrays:

array1 = [
"item1",
"item2",
"item3",
"item4"
];

array2 = [
"choice1",
"choice2",
"choice3",
"choice4"
];

我需要使array1变为：

I need to make array1 become this:

"item1",
"choice1",
"item2",
"choice2",
"item3",
"choice3",
"item4",
"choice4"
];

有人知道如何做吗？谢谢

Does anyone have any idea how to do this? Thanks

推荐答案

鉴于数组的长度与您可以映射到其中一个数组的长度相同，请使用这两个数组的索引处的两个值都相同，然后用concat展平以得到所需的结果。

Given that the arrays are the same length you can map over one of them, provide a return value of an array with both values at the index from both arrays, and then flatten with concat for your wanted result.

[].concat.apply([], array1.map((i, ind) => [i,array2[ind]]));

let a1 = ["item1","item2","item3","item4"], a2 = ["choice1","choice2","choice3","choice4"],
combined_array = [].concat.apply([], a1.map((i, ind) => [i,a2[ind]]));

console.log(combined_array);

OR

您可以类似地使用 reduce 。如果您不想远离Array对象调用 concat ，这可能是一个更好的选择：

You could similarly use reduce. This may be a better option if you would like to keep away from calling concat off an Array object:

array1.reduce((acc, i, ind) => acc.push(i, array2[ind])&&acc, []);

    let a1 = ["item1","item2","item3","item4"], a2 = ["choice1","choice2","choice3","choice4"],
    combined_array = a1.reduce((acc, i, ind) => acc.push(i, a2[ind])&&acc, []);
   

    console.log(combined_array);

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