char s []和char * s有什么区别？ [英] What is the difference between char s[] and char *s?

问题描述

在C语言中，可以在这样的声明中使用字符串文字：

In C, one can use a string literal in a declaration like this:

char s[] = "hello";

或类似这样：

char *s = "hello";

那么有什么区别？我想知道在编译和运行时在存储持续时间方面实际发生了什么。

So what is the difference? I want to know what actually happens in terms of storage duration, both at compile and run time.

推荐答案

此处的区别在于

char *s = "Hello world";

将 Hello world 放置在内存的只读部分，并且使 s 指向该内存的指针将使对该内存的任何写操作都非法。

will place "Hello world" in the read-only parts of the memory, and making s a pointer to that makes any writing operation on this memory illegal.

正在这样做：

char s[] = "Hello world";

将文字字符串放入只读内存中，并将该字符串复制到堆栈上新分配的内存中。因此，使

puts the literal string in read-only memory and copies the string to newly allocated memory on the stack. Thus making

s[0] = 'J';

合法。

这篇关于char s []和char * s有什么区别？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！