如何将Unix时间戳转换为DateTime,反之亦然? [英] How can I convert a Unix timestamp to DateTime and vice versa?
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问题描述
有这个示例代码,但是随后它开始讨论毫秒/纳秒级的问题。
There is this example code, but then it starts talking about millisecond / nanosecond problems.
MSDN上也有同样的问题, 自C#中的Unix时代以来第二秒 。
The same question is on MSDN, Seconds since the Unix epoch in C#.
这是我到目前为止所得到的:
This is what I've got so far:
public Double CreatedEpoch
{
get
{
DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, 0).ToLocalTime();
TimeSpan span = (this.Created.ToLocalTime() - epoch);
return span.TotalSeconds;
}
set
{
DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, 0).ToLocalTime();
this.Created = epoch.AddSeconds(value);
}
}
推荐答案
您需要什么:
public static DateTime UnixTimeStampToDateTime( double unixTimeStamp )
{
// Unix timestamp is seconds past epoch
System.DateTime dtDateTime = new DateTime(1970,1,1,0,0,0,0,System.DateTimeKind.Utc);
dtDateTime = dtDateTime.AddSeconds( unixTimeStamp ).ToLocalTime();
return dtDateTime;
}
或者,对于Java(这是不同的,因为时间戳以毫秒为单位,而不是秒):
Or, for Java (which is different because the timestamp is in milliseconds, not seconds):
public static DateTime JavaTimeStampToDateTime( double javaTimeStamp )
{
// Java timestamp is milliseconds past epoch
System.DateTime dtDateTime = new DateTime(1970,1,1,0,0,0,0,System.DateTimeKind.Utc);
dtDateTime = dtDateTime.AddMilliseconds( javaTimeStamp ).ToLocalTime();
return dtDateTime;
}
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