未定义JSONP跨域 [英] Undefined JSONP Cross Domain

查看:285
本文介绍了未定义JSONP跨域的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个基于PHP的超薄框架的API,并希望生成JSONP为我的网站。当我呼吁网站: http://api.mangayurdu.com/users?callback=JSON_CALLBACK 。它返回JSON回调()上写一个空白页。当登录到控制台是不确定的。

I have an API based on Php Slim Framework and want to generate JSONP for my website. When I call the website on: 'http://api.mangayurdu.com/users?callback=JSON_CALLBACK'. It returns a blank page with JSON CALLBACK() write on it. When logged to the console it is undefined.

API的index.php文件:

API's index.php:

<?php
require 'vendor/autoload.php';

$app = new \Slim\Slim();
$app->contentType('application/json');
$app->get('/users', 'getUsers');
$app->run();

function getConnection() {
$dbhost="localhost";
$dbuser="";
$dbpass="";
$dbname="";
$dbh = new PDO("mysql:host=$dbhost;dbname=$dbname;mysql:charset=utf8mb4", $dbuser, $dbpass);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

return $dbh;
}

function getUsers() {
$sql = "select * FROM manga";
try {
    $db = getConnection();
    $stmt = $db->query($sql);
    $users = $stmt->fetchAll(PDO::FETCH_OBJ);
    $db = null;
    echo $_GET['callback'] . '('.json_encode($users).')';
}
catch(PDOException $e) {
    echo $_GET['callback'] . '('.json_encode($e->getMessage()).')';
}
}

使用Javascript:

Javascript:

.factory('MY', function($http){
var fax= {};
var url = 'http://api.mangayurdu.com/users?callback=JSON_CALLBACK';
fax.isimler = $http.jsonp(url);
return fax;
})

.controller('indexCtrl', function($scope, MY) {
 MY.isimler.success(function(alHemen){
      $scope.mangas = alHemen;
 });  
})

在这里输入的形象描述

推荐答案

不要为它服务为应用程序/ JSON 。服务为应用程序/ JavaScript的。 JSONP需要被执行

Don't serve it as application/json. Serve it as application/javascript. JSONP needs to be executed.

此外,它似乎与修身你不应该使用回声。尝试调用 $ APP-GT&;响应 - 方式&gt; setBody

Also it appears with Slim you shouldn't use echo. Try calling $app->response->setBody.

这篇关于未定义JSONP跨域的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆