如何将std :: chrono :: time_point转换为字符串 [英] How to convert std::chrono::time_point to string

问题描述

如何将 std :: chrono :: time_point 转换为字符串？
例如： 201601161125 。

How to convert std::chrono::time_point to string? For example: "201601161125".

推荐答案

The最灵活的方法是将其转换为 struct tm ，然后使用 strftime （就像 sprintf ）。像这样的东西：

The most flexible way to do so is to convert it to struct tm and then use strftime (it's like sprintf for time). Something like:

std::chrono::system_clock::time_point now = std::chrono::system_clock::now();
std::time_t now_c = std::chrono::system_clock::to_time_t(now);
std::tm now_tm = *std::localtime(&now_c);
/// now you can format the string as you like with `strftime`

随意设置字符串格式在 strftime 此处。

Look up the documentation for strftime here.

如果您有 localtime_s 或 localtime_r 可用，您应该优先使用 localtime 。

If you have localtime_s or localtime_r available you should use either in preference to localtime.

还有很多其他方法可以执行此操作多数情况下更易于使用，它们导致了一些预定义的字符串表示形式。您可以将上述所有内容隐藏在一个易于使用的函数中。

There are many other ways to do this, but, while mostly easier to use, these result in some predefined string representation. You could just "hide" all of the above in a function for ease of use.

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