用const-correctness实现可变参数zip函数 [英] implementing a variadic zip function with const-correctness

问题描述

我正在尝试实现 zip 函数。 zip 的参数每个都是 wrapped< Ti> ，其中 Ti 因参数而异。

I'm trying to implement a zip function. zip's parameters are each wrapped<Ti>, where Ti varies from parameter to parameter.

zip 将这些 wrapped< Ti> s并产生 wrapped< tuple< T1&，T2&，... TN&> ，换句话说就是一个包裹的元组对其参数的引用。引用应该保留 const -ness。

zip takes these wrapped<Ti>s and produces a wrapped<tuple<T1&,T2&,...TN&>>, or in other words a wrapped tuple of references to its parameters. The references should preserve const-ness.

这是我第一次尝试 zip 具有一个参数，通常无法正常工作：

Here's my first stab at zip with one parameter, which doesn't work in general:

#include <utility>
#include <tuple>

// implement forward_as_tuple as it is missing on my system
namespace ns
{

template<typename... Types>
  std::tuple<Types&&...>
    forward_as_tuple(Types&&... t)
{
  return std::tuple<Types&&...>(std::forward<Types>(t)...);
}

}

template<typename T>
  struct wrapped
{
  wrapped(T &&x)
    : m_x(std::forward<T>(x))
  {}

  T m_x;
};

template<typename T>
  wrapped<std::tuple<T&&>>
    zip(wrapped<T> &&x)
{
  auto t = ns::forward_as_tuple(std::forward<T>(x.m_x));
  return wrapped<std::tuple<T&&>>(t);
}

int main()
{
  wrapped<int> w1(13);

  wrapped<int> &ref_w1 = w1;

  // OK
  zip(ref_w1);

  const wrapped<int> &cref_w1 = w1;

  // XXX won't compile when passing a const reference
  zip(cref_w1);

  return 0;
}

是否可以通过单一版本的 zip ？

Is there a way to implement the general, variadic case with a single version of zip?

推荐答案

这是我到达的解决方案：

Here's the solution I arrived at:

#include <utility>
#include <tuple>
#include <cassert>

template<typename T>
  struct wrapped
{
  wrapped(T &&x)
    : m_x(std::forward<T>(x))
  {}

  T m_x;
};

template<typename Tuple>
  wrapped<Tuple> make_wrapped_tuple(Tuple &&x)
{
  return wrapped<Tuple>(std::forward<Tuple>(x));
}

template<typename... WrappedTypes>
  decltype(make_wrapped_tuple(std::forward_as_tuple(std::declval<WrappedTypes>().m_x...)))
    zip(WrappedTypes&&... x)
{
  return make_wrapped_tuple(std::forward_as_tuple(x.m_x...));
}

int main()
{
  wrapped<int> w1(1);
  wrapped<int> w2(2);
  wrapped<int> w3(3);
  wrapped<int> w4(4);

  auto z1 = zip(w1,w2,w3,w4);

  z1.m_x = std::make_tuple(11,22,33,44);

  assert(w1.m_x == 11);
  assert(w2.m_x == 22);
  assert(w3.m_x == 33);
  assert(w4.m_x == 44);

  const wrapped<int> &cref_w1 = w1;

  auto z2 = zip(cref_w1, w2, w3, w4);

  // does not compile, as desired
  // z2.m_x = std::make_tuple(111,222,333,444);

  return 0;
}

具有 zip WrappedTypes ... 而不是 wrapped< T> ... 并不是令人满意的解决方案，但可以

Having zip take WrappedTypes... instead of wrapped<T>... isn't as satisfying a solution, but it works.

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