创建具有关联的表单 [英] Create a form with associations

问题描述

假设我有一个具有A hasMany B的模型A和B。我想制作一个表格，以允许用户添加模型A的实例，同时还可以添加尽可能多（关联）的模型A的实例。

Suppose I have a models A and B with A hasMany B. I would like to make a form to allow the user to add an instance of the model A, while also being able to add as many (associated) instances of the model B.

但是，做类似 echo $ this-> Form-> input（'ABsome_field'）在使用表单帮助器的表单中没有达到预期的效果。正确执行此操作的最佳方法是什么？

However, doing something like echo $this->Form->input('A.B.some_field') in the form using the form helper does not have the desired effect. What is the best way to do this properly?

推荐答案

关键是要具有与<$ c格式匹配的表单数据$ c>查找（'全部'） / saveAll（$ data）

The key is to have form data which matches the format of find('all')/saveAll($data)

您需要以下内容：

echo $this->Form->create('A');
echo $this->Form->input('A.id');

echo $this->Form->input('B.0.some_field');
echo $this->Form->input('B.1.some_field');
...

echo $this->Form->submit();
echo $this->Form->end();

生成的数据格式与saveAll期望的格式相同

That will generate data in the same format that saveAll expects

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