CakePHP 3.6.11：联接表的where子句 [英] CakePHP 3.6.11: Where clause of joined tables

问题描述

我有以下3个表：

客户：

客户可定制

服务：

服务稳定

customerservices：

customerservices:

customerservicestable

与此关系在 CustomerservicesTable.php 中：

$this->belongsTo('Customers')
            ->setForeignKey('customerid');

$this->belongsTo('Services')
            ->setForeignKey('serviceid');

在 Customers 编辑页面中包含特定客户服务的表（然后添加新客户，编辑现有客户等）。

In Customers edit page I want to add a table with the Services of the specific customer (and then add new, edit existing etc).

因此， Template\Customers\edit.ctp 我有此表：

<h3><?= __('Services') ?></h3>
    <table cellpadding="0" cellspacing="0">
        <thead>
            <tr>
                <th scope="col"><?= $this->Paginator->sort('Date') ?></th>
                <th scope="col"><?= $this->Paginator->sort('Service') ?></th>
                <th scope="col"><?= $this->Paginator->sort('Price') ?></th>
                <th scope="col" class="actions"><?= __('Actions') ?></th>
            </tr>
        </thead>
        <tbody>
            <?php foreach ($services as $service): ?>
            <tr>
                <td><?= h($service->created) ?></td>
                <td><?= h($service->title) ?></td>
                <td><?= $this->Number->format($service->price) ?></td>
                <td class="actions">
                    <?= $this->Html->link(__('View'), ['action' => 'view', $customer->id]) ?>
                    <?= $this->Html->link(__('Edit'), ['action' => 'edit', $customer->id]) ?>
                    <?= $this->Form->postLink(__('Delete'), ['action' => 'delete', $customer->id], ['confirm' => __('Are you sure you want to delete # {0}?', $customer->id)]) ?>
                </td>
            </tr>
            <?php endforeach; ?>
        </tbody>
    </table>

并在 edit 函数中c $ c> Controller\CustomersController.php 我添加了以下几行：

and in the edit function of Controller\CustomersController.php I have added these lines:

//Get customerservices for specific customer
        $servicesTable = TableRegistry::get('Services');
        $services = $servicesTable->find('all');//->where(['Services.Customerservices.id =' => $this->data['Customers']['id']]);

        $this->set(compact('services'));

我已经评论了 where 部分。如何更改它以便仅获得属于特定客户的服务？使用 customerservicesTable ？

And I have commented the where part. How I can change it in order to get only the services that belong to the specific customer? using the customerservicesTable?

之后，我可以直接编辑 CustomerservicesController.php 来实现此表的添加，编辑功能？

And after that can I edit directly the CustomerservicesController.php to implement the add,edit functions of this table?

EDIT

在ndm建议之后，我将其更改为：

After ndm suggestion I changed it like this:

//Get customerservices for specific customer
        $servicesTable = TableRegistry::get('Services');
        $services = $servicesTable->find()->matching('Customerservices', function(\Cake\ORM\Query $q) {
                return $q->where(['Customerservices.customerid' => $this->data['Customers']['id']]);
            });

但它不起作用。 $ this-> data ['Customers'] ['id'] 可能无法正常工作，因为如果我将其替换为1（客户ID），则其正常工作。知道为什么不起作用吗？

But its not working. Probably the $this->data['Customers']['id'] is not working because if I replace it with 1 (the Customer id) its working as expected. Any idea why is not working?

推荐答案

请尝试以下操作：

$servicesTable = TableRegistry::get('Services');

$customerId = $this->data['Customers']['id'];
// how about $this->request->getData('Customer.id') ?

// pass variable to function with `use`
$services = $servicesTable->find()->matching('Customerservices', function(\Cake\ORM\Query $q) use ($customerId) {
    return $q->where(['Customerservices.customerid' => $customerId]);
});

如果不确定 $ this-> data ['Customers '] ['id'] 包含您的期望，只是看看其中有什么：

If you are not sure that $this->data['Customers']['id'] contains what you expect, just have a look what’s in there:

debug($this->data['Customers']);

// or
debug($this->data);

// or
print_r($this->data['Customers']);

如果这是请求对象发布的数据，请在此处查看： https://book.cakephp.org/3.0/zh-CN/controllers/ request-response.html＃request-body-data

If this is data published by the Request Object, have a look here: https://book.cakephp.org/3.0/en/controllers/request-response.html#request-body-data

// An input with a name attribute equal to 'MyModel[title]' is accessible at
$title = $this->request->getData('MyModel.title');

这篇关于CakePHP 3.6.11：联接表的where子句的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！