定义TypeScript回调类型 [英] Defining TypeScript callback type

问题描述

我在TypeScript中拥有以下类：

I've got the following class in TypeScript:

class CallbackTest
{
    public myCallback;

    public doWork(): void
    {
        //doing some work...
        this.myCallback(); //calling callback
    }
}

我正在使用这样的类：

var test = new CallbackTest();
test.myCallback = () => alert("done");
test.doWork();

该代码有效，因此它按预期显示消息框。

The code works, so it displays a messagebox as expected.

我的问题是：我可以为我的课程字段 myCallback 提供任何类型吗？现在，公共字段 myCallback 的类型为 any ，如上所示。如何定义回调的方法签名？还是可以将类型设置为某种回调类型？还是我可以做这些？我必须使用 any （隐式/显式）吗？

My question is: Is there any type I can provide for my class field myCallback? Right now, the public field myCallback is of type any as shown above. How can I define the method signature of the callback? Or can I just set the type to some kind of callback-type? Or can I do nether of these? Do I have to use any (implicit/explicit)?

我尝试过类似的操作，但是没有工作（编译时错误）：

I tried something like this, but it did not work (compile-time error):

public myCallback: ();
// or:
public myCallback: function;

我在网上找不到对此的任何解释，希望您能帮帮我。

I couldn't find any explanation to this online, so I hope you can help me.

推荐答案

我刚刚在TypeScript语言规范中找到了一些东西，这很容易。我非常接近。

I just found something in the TypeScript language specification, it's fairly easy. I was pretty close.

语法如下：

public myCallback: (name: type) => returntype;

在我的示例中，应该是

class CallbackTest
{
    public myCallback: () => void;

    public doWork(): void
    {
        //doing some work...
        this.myCallback(); //calling callback
    }
}

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