注意：未定义的变量：第11行的C：wamp\projects\ServiceAdmin\login\loginauth.php中的验证码 [英] Notice: Undefined variable: captcha in C:\wamp\projects\ServiceAdmin\login\loginauth.php on line 11

问题描述

我目前正在为一个项目创建登录脚本，但尝试引入验证码已证明存在问题；

I am currently creating a login script for a project, yet trying to introduce a captcha has proven issues with it; of which I am not entirely certain of.

登录页面：

表单：

格式代码：

    <div class="col-lg-8">
    <script src="https://www.google.com/recaptcha/api.js"></script>
      <form class="form-signin" method="post" action="loginauth.php">
        <h2 class="form-signin-heading">Sign in to ServiceAdmin</h2><br>
        <label class="sr-only">Email address</label>
        <input name="email" type="email" class="form-control" placeholder="Email address" required autofocus>
        <label class="sr-only">Password</label>
        <input name="password" type="password" class="form-control" placeholder="Password" required><br>
    </div>
    <div class="col-lg-4">
        <div class="g-recaptcha" style="margin-top: 115px; margin-left: 20px;" data-sitekey="REDACTED"></div>

        <?php if($_SESSION['login.captcha']){
            echo '<font color="red"><p style="margin-left:27px;">Please tick this checkbox to verify your security.</p></font>';
            unset($_SESSION['login.captcha']);
          } else {
            echo '<p style="margin-left:27px;">Please tick this checkbox to verify your security.</p>';
          } ?>

        </div><br><br>
        <input class="btn btn-lg btn-primary btn-block" type="submit" value="Sign in">
      </form>

登录后端代码（loginauth.php）：

<?php
error_reporting(E_ALL);
$email = $password = $captcha = NULL;
if(isset($_POST['email'])){
  $email = $_POST['email'];
}
if(isset($_POST['password'])){
  $password = $_POST['password'];
}
if(isset($_POST['g-recaptcha-response'])){
  $captcha = $_POST['g-recaptcha-response'];
}
if(!$captcha){
  echo "captcha error";
  exit;
}

$response=file_get_contents("https://www.google.com/recaptcha/api/siteverify?secret=REDACTED&response=".$captcha."&remoteip=".$_SERVER['REMOTE_ADDR']);
if($response.success==false){
  "captcha error bot";
} else {
  "success";
}
?>

无论如何，尽管填写了验证码，但它不会被识别为已输入，并且会出现这样的错误：

No matter what, despite the captcha being filled in, it will not be recognized as entered, and will come up with error as such:

( ! ) Notice: Undefined variable: captcha in C:\wamp\projects\ServiceAdmin\login\loginauth.php on line 11

如果有人对

推荐答案

如果您引用的变量尚未创建，PHP会发出通知

PHP throws notices if you reference a variable that hasn't been created yet, although the code still "works".

在这种情况下， $ captcha 永远不会实例化，因为您的代码永远不会到达创建它的行

In this case, $captcha is never instantiated because your code never reaches the line that creates it

if（isset（$ _ POST ['g-recaptcha-response']））{
$ captcha = $ _POST ['g-recaptcha-response'];
}

常见的解决方法是使用声明 $ captcha 在第11行上使用/引用它之前，返回false或null值。

The common fix is to declare $captcha with a false or null value before you use/reference it on line 11.

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