-bash：php：找不到命令-Centos6.7 [英] -bash: php: command not found - Centos6.7

问题描述

我在服务器上安装了两个版本的PHP：

I have two versions of PHP installed on the server:

$ find / -name php -type f

结果：

/opt/rh/php54/root/usr/bin/php
/opt/rh/php55/root/usr/bin/php

我已将php54路径添加到〜/ .bash_profile

I've added php54 path to ~/.bash_profile

$ echo $PATH

结果：

/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin:/root/bin:/opt/rh/php54/root/usr/bin/php

但是 $ php -v 仍然不起作用。

实际上，如果我 $ cd / opt / rh / php54 / root / usr / bin 并从目录本身运行 php -v ，它仍然不会工作。我得到：

in fact if I $ cd /opt/rh/php54/root/usr/bin and run php -v from the directory itself, it still doesn't work. I get:

-bash: php: command not found

已安装PHP，因为有网站在运行，只是命令行无法正常工作...

PHP is installed as there are websites running, just command line is not working...

两者

php55-php-cli-5.5.21-4.el6.x86_64
php54-php-cli-5.4.40-2.el6.x86_64

已安装...

推荐答案

错误的路径：

查找结果：

/opt/rh/php54/root/usr/bin/php
                           ^^^--- your php binary

$ PATH仅期望 DIRECTORIES 。您在$ PATH中列出了上述路径，这意味着Shell将搜索 ... / usr / bin / php / php 。请注意加倍的 php 。第一个是您在$ PATH中添加的目录，第二个是您尝试运行的程序。 $ PATH条目应为 ... / usr / bin / ，而没有 php 。

$PATH expects only DIRECTORIES. You listed the above path in $PATH, which means that the shell will be searching for .../usr/bin/php/php. Note the doubled php. First one is the "directory" that you added in $PATH, while the second one is the program you're trying to run. The $PATH entry should be JUST .../usr/bin/, WITHOUT the php.

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