给定一个字符串查找出现的位置并替换为另一个字符串而不使用string.replace（） [英] Given a string find occurrences and replace with another string without using string.replace()

问题描述

这里是我要实现的示例：例如，给定字符串某事，如果要替换所有出现的 so 与DDD ，结果将为 DDD方法。

Here is an example of what I want to implement: for instance, given the string Something, if you were to replace all occurrences of so with DDD, the result would be DDDmething.

这是我实现它的方式；我的代码按其特定位置找到了一个字符并对其进行了更改，但实际上我想实现上面所说的内容。

Here is how I am implementing it; my code finds a char by its specific position and changes it, but in fact I want to implement what I stated above.

    static void Main(string[] args)
    {
        string str = "The Haunting of Hill House!";
        Console.WriteLine("String: " + str);

        // replacing character at position 7
        int pos = 7;
        char rep = 'p';

        string res = str.Substring(0, pos) + rep + str.Substring(pos + 1);
        Console.WriteLine("String after replacing a character: " + result);

        Console.ReadLine();
    }

推荐答案

替代方案可能是拆分按 so字符串，并按 DDD加入结果数组：

Alternative might be to split the string by "so" and join the resulting array by "DDD" :

string result = string.Join("DDD", "something".Split(new[] { "so" }, StringSplitOptions.None));

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