在不按Enter的情况下获取单个字符 [英] Getting a single character without pressing enter

问题描述

我正在尝试从用户那里输入单个字符，而无需用户按Enter。我已经尝试过：

I'm trying to get a single character input from the user without the user having to press enter. I've tried this:

#include <stdio.h>

int main() {
    int input;

    for (;;) {
        input = getchar();
        printf("%d\n", input);
    }
}

但用户不仅需要按Enter，它还记录了两次按下（输入字符和换行符），即：

But not only does the user need to press enter, it also registers two presses (the input character and the newline character) ie:

$ ./tests
a
97
10
c
99
10

因为我总是希望用户输入一个字符，并且希望将此字符作为 char 或 int ，如何在不等待 \n 的情况下获得角色。

Since I will always expect exactly one character input from the user, and want this character as either a char or an int, how can I get the character without waiting for a \n.

我也尝试使用 fgets ，但是由于我在循环中等待用户输入，因此它会连续执行 printf 而不会阻塞直到输入。

I also tried using fgets, but because I'm in a loop waiting for user input, that just continously executes the printf without blocking until input.

我的预期输出为：

a97
b98
...

NB：我目前正在使用OSX，但我很高兴

NB: I'm currently on OSX but I'm happy with a solution that applies to either OSX or Linux.

推荐答案

我最近需要exac

I have recently needed exactly the same feature and I have implemented it in the following way:

#include <stdlib.h>

char c;

system("/bin/stty raw");
c = tolower(getchar());
system("/bin/stty cooked");

查看 man stty ，我认为它应该在Linux和Mac OS X上都可以使用。

Looking at man stty, I think it should work on both Linux and Mac OS X.

编辑：所以您的程序看起来像（您需要向其中添加信号处理程序）：

So your program would look like (you would need to add a signal handler to it):

#include <stdlib.h>
#include <stdio.h>

int main() {
    int input;

    for (;;) {
        system("/bin/stty raw");
        input = getchar() - '0';
        printf("%d\n", input);
        system("/bin/stty cooked");
    }
    return 0;
}

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