如何在配方编辑时读取食谱文件？ [英] How to read cookbook file at recipe compilation time?

问题描述

这种事情在厨师食谱中很常见：

This kind of thing is commonly seen in Chef recipes:

%w{foo bar baz}.each do |x|
  file "#{x}" do
    content "whatever"
  end
end

但是我想从菜谱保存的文件中读取要循环播放的项目，例如：

But I want to read the items to loop over from a file which is kept with the cookbook, for example:

File.open('files/default/blah.txt').each do |x|
  file "#{x}" do
    content "whatever"
  end
end

如果我给出 blah.txt 的完整路径，则该方法有效，厨师客户端恰巧将其缓存，但它不可移植。如果我像在示例中希望那样将当前目录作为食谱的根目录，则无法正常工作。

This works if I give the full path to blah.txt where chef-client happens to cache it, but it's not portable. It doesn't work if I write it like in the example, "hoping" that the current directory is the root of the cookbook. Is there a way to obtain the cookbook root directory as the recipes are compiled?

推荐答案

另一种解决方案，对于那些不喜欢的人，是否可以通过获取食谱来获取食谱的根目录？在收敛之前需要文件内容，但是不需要任何client.rb修改的文件是使用cookbook_file将资源读取到file_cache_path中，然后延迟加载它。这是一个示例，其中我读取了要嵌入到xml模板中的常规脚本。

Another solution, for those who don't need the file content until converge time, but one that does not require any client.rb modifications, is to use cookbook_file to read the resource into your file_cache_path and then lazy load it. Here is an example where I read in a groovy script to be embedded into an xml template.

script_file = "#{Chef::Config['file_cache_path']}/bootstrap-machine.groovy"
cookbook_file script_file do
    source 'bootstrap-machine.groovy'
end

config_xml = "#{Chef::Config['file_cache_path']}/bootstrap-machine-job.xml"

template config_xml do
    source 'bootstrap-machine-job.xml.erb'
    variables(lazy {{
        :groovy_script => File.open(script_file).read
    }})
end

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