NodeJ的child_process工作目录 [英] NodeJs child_process working directory

问题描述

我正在尝试执行子进程在与以下目录不同的目录中它的父母。

I am trying to execute a child process in a different directory then the one of its parent.

var exec = require('child_process').exec;

exec(
    'pwd',
    {
        cdw: someDirectoryVariable
    },
    function(error, stdout, stderr) {
        // ...
    }
);

我正在执行上述操作（尽管运行 pwd当然不是我想要做的到底）。不管我为cdw选项提供什么值，最终都会将父进程的pwd写入stdout。

I'm doing the above (though of course running "pwd" is not what I want to do in the end). This will end up writing the pwd of the parent process to stdout, regardless of what value I provided to the cdw option.

我缺少什么？

（我确实确保通过cwd选项传递的路径确实存在）

(I did make sure the path passed as cwd option actually exists)

推荐答案

当前工作目录的缩写，缩写为 cwd ，而不是 cdw 。

The option is short for current working directory, and is spelled cwd, not cdw.

var exec = require('child_process').exec;
exec('pwd', {
  cwd: '/home/user/directory'
}, function(error, stdout, stderr) {
  // work with result
});

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