使用子进程NodeJS运行exe文件 [英] Run exe file with Child Process NodeJS

问题描述

我想使用nodejs打开谷歌浏览器，但出现此错误（我使用execFile和spawn），

I want to open google chrome with nodejs, but I get this error (I used execFile and spawn),

code

var execFile = require('child_process').execFile,
spawn = require('child_process').spawn,

spawn('C\\Program Files\\Google\\Chrome\\Application\\chrome.exe', function (error, stdout, stderr) {
   if (error !== null) { console.log('exec error: ' + error); }
});

events.js:72
    throw er; // Unhandled 'error' event
          ^
Error: spawn ENOENT
at errnoException (child_process.js:998:11)
at Process.ChildProcess._handle.onexit (child_process.js:789:34)

推荐答案

每个命令都在一个单独的shell，因此第一个cd仅影响该shell进程，然后终止。如果要在特定目录中运行git，只需让Node为您设置路径：

Each command is executed in a separate shell, so the first cd only affects that shell process which then terminates. If you want to run git in a particular directory, just have Node set the path for you:

exec('git status', {cwd: '/home/ubuntu/distro'}, /* ... */);

cwd（当前工作目录）是可用于exec的众多选项之一。请参阅链接

cwd (current working directory) is one of many options available for exec.refer to link

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