如何派生另一个模块的进程 [英] How to fork a process of another module

问题描述

TL; DR：如何分叉当前运行进程之外的进程？

TL;DR : How does one fork a process that is located outside of the current running process?

我尝试使用Nodejs的 child_process 以便在父进程的出口退出时启动另一个nodejs进程。

I'm trying to use child_process of Nodejs in order to start another nodejs process on the parent's process exit.

我使用 exec 成功执行了该过程，但是我需要子进程独立于父进程，因此父进程可以退出而无需等待子进程，因此我尝试使用 spawn ，其中 detached：true，stdio：'ignore'选项和 unref（）进程：

I successfully executed the process with the exec but I need the child process be independent of the parent, so the parent can exit without waiting for the child, hence I tried using spawn with the detached: true, stdio: 'ignore' option and unref()ing the process:

设置options.detached为true使得子进程可以在运行后继续运行父级退出。

setting options.detached to true makes it possible for the child process to continue running after the parent exits.

spawn（'node MY_PATH'，[]，{分离：true，stdio：' ignore'}）。unref（）;

这将产生：

节点MY_PATH ENOENT 错误。

在使用 spawn 实现此操作并阅读文档再次，我认为我应该实际使用 fork ：

After having troubles achieving this with spawn and reading the documentationagain i figured i should actually use fork:

child_process.fork（）方法是child_process.spawn（）的特例，专门用于生成新的Node.js进程。

The child_process.fork() method is a special case of child_process.spawn() used specifically to spawn new Node.js processes.

fork（）并不将命令作为其第一个参数，但是 modulePath 我似乎不合适，因为我尝试作为子进程运行的脚本不在当前运行进程的目录中，而是依赖于

fork() doesnt take a command as its' first argument, but a modulePath which i can't seem to fit since the script I'm trying to run as a child process isnt in the directory of the current running process, but in a dependency of his.

回到起始TL; DR-如何分叉位于当前运行进程之外的进程？

Back to the starting TL;DR - how does one fork a process that is located outside of the current running process?

任何帮助将不胜感激！

编辑：

为 spawn ENOENT错误提供解决方案也可能非常有帮助！

Providing a solution to the spawn ENOENT error could be very helpfull too!

推荐答案

下面的代码应允许您执行所需的操作。

Following code should allow you to do what you need.

var Path = require('path');
var Spawn = require('child_process').spawn;

var relative_filename = '../../node_modules/bla/bla/bla.js';

Spawn('node', [Path.resolve(__dirname, relative_filename)], {detached: true, stdio: 'ignore'}).unref();

process.exit(0);

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